The answer is whole
Hope this helps
Answer:
see explanation
Step-by-step explanation:
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If in the triangle ABC , BF is an angle bisector and ∠ABF=41° then angle m∠BCE=8°.
Given that m∠ABF=41° and BF is an angle bisector.
We are required to find the angle m∠BCE if BF is an angle bisector.
Angle bisector basically divides an angle into two parts.
If BF is an angle bisector then ∠ABF=∠FBC by assuming that the angle is divided into two parts.
In this way ∠ABC=2*∠ABF
∠ABC=2*41
=82°
In ΔECB we got that ∠CEB=90° and ∠ABC=82° and we have to find ∠BCE.
∠BCE+∠CEB+EBC=180 (Sum of all the angles in a triangle is 180°)
∠BCE+90+82=180
∠BCE=180-172
∠BCE=8°
Hence if BF is an angle bisector then angle m∠BCE=8°.
Learn more about angles at brainly.com/question/25716982
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Answers:
f(-3) = -1
f(-1) = 2
f(3) = 5
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Explanations:
Draw a vertical line through -3 on the x axis. Make sure this vertical line crosses the orange graph. Mark this point of intersection and then draw a horizontal line from this point to the y axis. You should find that it touches -1 on the y axis. Check out the attached image to see this process in action.
Those steps basically say that x = -3 leads to y = -1. Since y = f(x), this means f(-3) = -1
Through similar steps, you should find that f(-1) = 2 and f(3) = 5
Note that the open hole/circle does not count. So if you land on an open hole, just keep going until you hit a closed circle on the other piece of the graph.
Okay so i would do this with a logarithm.
5^(2x) = 28
take the log of both sides
log5^(2x) = log28 and because of this log rule: logA^n = nlogA
(2x)log5= log28
then divide by log5 on both sides
2x = log28 / log5
and divide by 2
x = (log28 / log5) /2
this can be found with a calculator:
x= about 1.03521...
round that to whatever the question says to