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zepelin [54]
4 years ago
15

1. The length of a rectangle is 90 in. Its area is less than 380 in-. What is the

Mathematics
1 answer:
Tamiku [17]4 years ago
7 0

To find the area of a rectangle, do length times width. Because we know the length (90 in), we can divide 380 by 90 to find the maximum possible width. This is possible because of the equation width = Area/length, which is derived from width * length = Area. 380/90 = 4.222, so the maximum width to the nearest possible inch is 4 inches.

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Kenny's Designs sells 140 shirts and 63 hats per week. Which of the following equations can be used to calculate the number of h
antoniya [11.8K]

The answer would be C because 63 hats were sold and nine would be the amount of shirts he sold in x amount of days

5 0
3 years ago
You have a job that’s pays $15.00 an hour. You really want to get geared up. How many hours do you need to work in order to save
dolphi86 [110]
Use Photomath trust me is better than brainly
7 0
4 years ago
F(x)=-9x+8 then f(-2)=?
Flura [38]

Answer:

26

Step-by-step explanation:

the function is f(x), and we need to find f(-2). the only difference between the two terms i gave is the -2 replacing the x. this means that you must replace every x in the first equation with -2. this makes the new function f(-2)=-9(-2)+8. after multiplying the -9 and -2 and adding that product to 8, you come up with your answer: 26.

8 0
3 years ago
Read 2 more answers
Find the length of the line segment formed by the points (2, 3) and (2, 5)
SCORPION-xisa [38]

Answer:

2 units

Step-by-step explanation:

Given data

The points are  (2, 3) and (2, 5)

x1= 2

y1= 3

x2= 2

y2= 5

substitute into the distance between two points formula

d=√((x_2-x_1)²+(y_2-y_1)²)

d=√((2-2)²+(5-3)²)

d=√(2)²)

d=√4

d= 2 units

Hence the length is 2 units

3 0
3 years ago
It cost marci 33 cents to mail a postcard and 49 cents to mail a letter. she sent either a postcard or a letter to each of 28 pe
Rus_ich [418]

Answer:

24 Letters and 4 Postcards

Step-by-step explanation:

We have to set up a system of equations, since we have two unknown variables. Lets say postcards is the variable "x" and letters is the variable "y".

Our first equation will be the money spent: 0.33x + 0.49y = 13.08, this comes from knowing that it costs 0.33 dollars to mail a postcard and 0.49 dollars to send a letter.

The second equation is the total sent: x + y =28.

Now we need to solve for a single variable, let's do y (or letters). If we subtract y from both sides we get: x = 28 - y.

We can plug that into our first equatino to get: 0.33(28 - y) + 0.49y = 13.08.

If we multiply things out we get: 9.24 - 0.33y + 0.49y = 13.08, and now we have like terms. 9.24 + 0.16y = 13.08.

Subtract 9.24 from both sides to get: 0.16y = 3.84

Divide both sides by 0.16 to get: y = 24.

Now we can plug this into x + y = 28 to see that x= 4.

You could make sure this is correct by solving for x instead of y and do the same process.

Hope this helps.

4 0
3 years ago
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