If B is the midpoint of AC, then AB=BC. It is also BC=AC-AB
AB = x + 6
AC = 5x - 6
BC = (5x - 6) - (x + 6)
We can kinda use distributive property, like this:
BC = 5x - 6 -x - 6
Combine like terms:
BC = 4x - 12
To verify, we can add AB and BC to see if their sum is equal to AC.
(x + 6) + (4x - 12) = 5x - 6
If we are correct, this equation will be true.
x + 6 + 4x - 12 = 5x - 6
Combine like terms:
6 + 5x - 12 = 5x - 6
5x - 6 = 5x - 6
It's correct!
BC = 4x - 12. Final Answer.
Let me know if you have any questions about this! :)
It would be log3 14/log3 4
Hope this helps. (:
So I'm guessing that the x2 is your way of saying 2 is the exponent right? In that case the equation would be 8x^2 + 12x
Well you would have to pull out the gcf which in this case will be 4x after pulling out the gcf you should get 4x(2x + 3)
Answer:
y =0
Step-by-step explanation:
From the equation;
8³ × 8⁻⁵×8^y = 8⁻²= 1/8²
From the laws of indices;
aⁿ×aⁿ = a^2n
Therefore;
8³ × 8⁻⁵×8^y = 8^(3+-5+y)
8^(-2+y) = 8^-2 ; but the bases are the same and thus the exponents are the same;
-2 + y = -2
y = 0
(1, 3.5 ) and (3, 3.5 )
the endpoints of the midsegment are at the midpoints of DE and DF
using the midpoint formula with D(0, 7), E(2, 0), F(6, 0)
midpoint of DE = [
(0 + 2),(7 + 0)] = (1, 3.5)
midpoint of DF = [(0 + 6),(7 + 0)] = (3, 3.5)
