Let 
be the speed of train A, and let's set the origin in the initial position of train A. The equations of motion are
where 
are the positions of trains A and B respectively, and t is the time in hours.
The two trains meet if and only if 
, and we know that this happens after two hours, i.e. at 
Solving this equation for v we have
So, train A is travelling at 105 km/h. This implies that train B travels at
Package A = $276 for 12 tickets (2 x 6) // 276 divided by 12 = $23 per ticket
Package B = $336 for 16 tickets (2 x 8) // 336 divided by 16 = $21 per ticket
$23 - $21 = $2
Package A charges $2 more per ticket.
Answer:
The answer is 50%.
Step-by-step explanation:
I did the question on IXL, and got it right.
14.7x + 4x = 0*(49y+39y) y = 14
18.7x = 0(686 + 546)
18.7x = 0
x = 0
Answer: 2/3x-12=48
remember that less than means it goes to the back
