3 years ago

If 3(r+300)=6, then what would be the value of r+300-2?

Mathematics

1 answer:

saveliy_v [14]3 years ago

6 0

Solve for r in the first equation:

3(r+300) = 6

Use the distributive property:

3r + 900 = 6

Subtract 900 from both sides:

3r = -894

Divide both sides by 3:

r = -894 / 3

r = -298

Now you have r, replace r in the second equation and solve:

r +300 -2 =

-298 + 300 - 2 = 0

The answer is 0.

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