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jenyasd209 [6]
3 years ago
5

Which is correct regarding the statement: "fx is an odd Integer, then the median of x, X + 2, X + 6, and x + 10 is an odd number

"
the statement is always true
there is not enough information provided to answer the question
the statement is always false
the statement is sometimes true
Mathematics
1 answer:
PSYCHO15rus [73]3 years ago
3 0

Answer:

The statement is always true

Step-by-step explanation:

We have,

x, x+2, x+6, x+10

There are even number of terms. So for the median we add the two middle terms and divide it by 2.

Median = (x+2+x+6)/2

= (2x+8)/2

= 2(x+4)/2

= x+4

As we know that an odd number is always odd number if we add some even number to it.

In the question, x is an odd integer so, if we add 4 then it would be again an odd integer. Therefore, the median is also an odd integer.

The statement is always true.

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A company manufactures 2,000 units of its flagship product in a day. The quality control department takes a random sample of 40
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The yard behind the Cindy’s house is rectangular in shape and has a perimeter of 72 feet. If the length l of the yard is 18 feet
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Let
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</span>
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How do you solve this?
Bogdan [553]

Answer:

  x = y = (15/2)√2

Step-by-step explanation:

You can recognize this as an isosceles right triangle, so x=y. They Pythagorean theorem then tells you that ...

  15² = x² + x²

  225/2 = x²

  √(225/2) = x = √(225·2/4) = (15/2)√2

The solution is x = y = (15/2)√2.

_____

<em>Comment on isosceles right triangles</em>

It is worth remembering that the ratio of sides of an isosceles right triangle is ... side : side : hypotenuse = 1 : 1 : √2.

Knowing this lets you write down the solution to this problem as ...

  x = y = 15/√2

Of course, the denominator of this fraction can be rationalized by multiplying the fraction by (√2)/(√2) to get (15√2)/2 or (15/2)√2.

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