Given:
A line passes through (1,-2) and is perpendicular to 
.
To find:
The equation of that line.
Solution:
We have, equation of perpendicular line.
Slope of this line is
Product of slope of two perpendicular lines is -1.
Now, slope of required line is 
and it passes through (1,-2). So, the equation of line is
where, m is slope.
Therefore, the equation of required line is .
Answer:
A, D,F are triangle sides
Answer:
xyz plz my answer as brainliest
Answer:
c = 1.45
Step-by-step explanation:
Solving the equation for c, we find ...
p +e = nc
c = (p +e)/n
Filling in the values given, we have ...
c = (4050 +300)/3000 = 4350/3000 = 1.45
The value of c is 1.45.
Y= x^2-58
X^2-58=0
X^2=58
X= sqrt of 58
X= 7.6
Y= x^2+13
X^2+13=0
X^2=-13
Get sq rt of 13 the negative becomes i
X= 3.6i
