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Marina CMI [18]
3 years ago
7

Given a rectangle with a perimeter of 24 inches, why dimensions maximize the area?

Mathematics
1 answer:
Pepsi [2]3 years ago
5 0

Answer:

The dimensions are 6 by 6

Step-by-step explanation:

Calculus answer:

2x +2y= 24

xy= A

2x=24-2y

x=12-y

(12-y)(y)= 12y- y^2

the Derivative is = 12-2y

Then set that equal to zero 0=12-2y

-12=-2y

y=6

Confirm that 6 is a maximum by using a wiggle graph

wiggle graph -∞<---inc--6---dec-->∞

6 is a maximum

plug into original equation

2x + 2(6)=24

2x+12=24

2x=12

x=6

----------------------------------------------------------------------------------------------------

y=6

x=6


     



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A swimming pool is represented on a coordinate grid with the following vertices: Vertex A is at (−2,−3) . Vertex B is at ​​ (−2,
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Answer:

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Step-by-step explanation:

We can find the distance walked by Jared by finding the distances between each of the given vertex of swimming pool. We will use distance formula to find the distances between each vertex.  

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\text{Distance between vertex A and vertex B}=\sqrt{64}=8

Now let us find distance between vertex B and vertex C.

\text{Distance between vertex B and vertex C}=\sqrt{(-2-3)^{2}+(5-5)^{2}}

\text{Distance between vertex B and vertex C}=\sqrt{(-5)^{2}+(0)^{2}}

\text{Distance between vertex B and vertex C}=\sqrt{25}=5

Now let us find distance between vertex C and vertex D.

\text{Distance between vertex C and vertex D}=\sqrt{(3-3)^{2}+(5--3)^{2}}

\text{Distance between vertex C and vertex D}=\sqrt{(0)^{2}+(5+3)^{2}}

\text{Distance between vertex C and vertex D}=\sqrt{64}=8

Now let us find distance between vertex D and vertex A.

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\text{Distance between vertex D and vertex A}=\sqrt{(3+2)^{2}+(-3+3)^{2}}    

\text{Distance between vertex D and vertex A}=\sqrt{(5)^{2}+(0)^{2}}

\text{Distance between vertex D and vertex A}=\sqrt{25}=5

Now let us add all these distances to find the total distance walked by Jared.  

\text{Total distance walked by Jared}=8+5+8+5

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Since we have been given that one unit on the grid equals 1 yard,   therefore, Jared walked a distance equal to 26 yards.  

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Answer:

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