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sveta [45]
3 years ago
11

there are 6 times as many dogs as cAts. if tje total number of dogs and cats is 21 how many dogs are tjrre

Mathematics
1 answer:
frez [133]3 years ago
5 0
There are 18 dogs. You do 21/7.


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The cost of a taxi ride is represented by the function c(m)=2m+4, where m is the number of miles traveled. What is the cost per
deff fn [24]

Answer:

$6

Step-by-step explanation:

We have: The cost of a taxi ride is represented by the function c(m)=2m+4

Plug 1 mile into "m" of the function c(m)=2m+4

So, we have c (1) = 2 ˣ 1 + 4 = 6

Thus, The cost per mile of the cab is $6.

8 0
3 years ago
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I’ve saved £264. I will spend 3/12 of this. How much do I have left?
lara [203]
Hi there! The answer is £198.

If you spend 3 / 12 of a certain amount of money, you have 9 / 12 of the money left.

Simplify the fraction.
9 / 12 = 3 / 4.

To find the amount of money left, we multiply this factor by 264. We get the following
£264 × 3/4 = £264 × 0.75 = £198

Therefore the answer is £198
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3 years ago
Use the compound interest formula to compute the total amount accumulated and the interest earned.
mezya [45]
A=3,500×(1+0.011÷12)^(12×4)
A=3,657.36

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6 0
3 years ago
ANSWER THIS AND ILL LOVE YOU <br><br> find angles FAB and BAC
jeyben [28]

Answer:

m<FAB = 75°

m<BAC = 105°

Step-by-step explanation:

First, find the value of x.

(13x - 3)° = (3x + 2)° + 55° (exterior angle theorem of a ∆)

Solve for x

13x - 3 = 3x + 2 + 55

13x - 3 = 3x + 57

Collect like terms

13x - 3x = 57 + 3

10x = 60

Divide both sides by 10

x = 6

✔️m<FAB = 13x - 3

Plug in the value of x

m<FAB = 13(6) - 3 = 78 - 3

m<FAB = 75°

✔️m<BAC = 180 - m<FAB (angles on a straight line/supplementary angles)

m<BAC = 180 - 75 (substitution)

m<BAC = 105°

4 0
2 years ago
Definition of classic probability
12345 [234]
Classical probability is the statistical concept that measures the likelihood of something happening, but in aclassic sense, it also means that every statistical experiment will contain elements that are equally likely to happen.
7 0
3 years ago
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