28 ft per min = 0.512064 km per hour
Answer:
i.e. relation between speed-distance-time is one such situation that can be modeled using graph
Step-by-step explanation:
There are many real world examples that can be modeled using graph. Graphs are represented on co-ordinate planes, so any real world example that can be represented by use of linear equation can be represented onto a graph.
One such example, is speed-distance-time relation. Uniform speed can be represented on a graph as shown in figure.
So, the equation for speed is represented by equation as follows:

So, if we take distance on y axis and time on x axis with points as (distance,time)
(0,0) ==> 
(1,2) ==> 
(2,2) ==> 
the following points 0,0.5,1 will be plotted on graph. Similarly, more values can be plotted by assuming values for distance and time.
Answer:
divide the figure into two parts.
area of triangle = 1/2×base×height
area of triangle = 1/2×3×3
area pf triangle = 4.5 units²
area of square = side²
area of square = 3²
area of square = 9unit²
Answer:
The answer is 1.5
Step-by-step explanation:
Answer:
See below
Step-by-step explanation:
In #4, the angles are vertical because the angles are congruent to each other. Therefore, you would set up the equation x+8=120 where x=112.
In #5, the angles are complementary because their sum is 90°. Therefore, you would set up the equation 43+x+3=90 where x=44.
In #6, the angles are supplementary because their sum is 180°. Therefore, you would set up the equation 76+2x+4=180 where x=50.