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2 years ago

Mary has a brownie recipe that calls for baking the brownies at 190°C for about 25 to 30 minutes.

Mathematics

1 answer:

alisha [4.7K]2 years ago

6 0

Answer:

374°F

Step-by-step explanation:

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3 divided by 11/12 I need the answer ASAP

s344n2d4d5 [400]

36/11

Calculator solves everything

8 0

2 years ago

These points are linear.

posledela

Answer:

Step-by-step explanation:

Select an ordered pair: (2, 7)

Select another ordered pair: (6, 19)

slope = (difference in y)/(difference in x)

slope = (19 - 7)(6 - 2)

slope = 12/4

slope = 3

4 0

2 years ago

Read 2 more answers

Prove or disprove (from i=0 to n) sum([2i]^4) <= (4n)^4. If true use induction, else give the smallest value of n that it doe

ddd [48]

Answer:

The statement is true for every n between 0 and 77 and it is false for $n\geq 78$

Step-by-step explanation:

First, observe that, for n=0 and n=1 the statement is true:

For n=0: $\sum^{n}_{i=0} (2i)^4=0 \leq 0=(4n)^4$

For n=1: $\sum^{n}_{i=0} (2i)^4=16 \leq 256=(4n)^4$

From this point we will assume that $n\geq 2$

As we can see, $\sum^{n}_{i=0} (2i)^4=\sum^{n}_{i=0} 16i^4=16\sum^{n}_{i=0} i^4$ and $(4n)^4=256n^4$ . Then,

$\sum^{n}_{i=0} (2i)^4 \leq(4n)^4 \iff \sum^{n}_{i=0} i^4 \leq 16n^4$

Now, we will use the formula for the sum of the first 4th powers:

$\sum^{n}_{i=0} i^4=\frac{n^5}{5} +\frac{n^4}{2} +\frac{n^3}{3}-\frac{n}{30}=\frac{6n^5+15n^4+10n^3-n}{30}$

Therefore:

$\sum^{n}_{i=0} i^4 \leq 16n^4 \iff \frac{6n^5+15n^4+10n^3-n}{30} \leq 16n^4 \\\\ \iff 6n^5+10n^3-n \leq 465n^4 \iff 465n^4-6n^5-10n^3+n\geq 0$

and, because $n \geq 0$ ,

$465n^4-6n^5-10n^3+n\geq 0 \iff n(465n^3-6n^4-10n^2+1)\geq 0 \\\iff 465n^3-6n^4-10n^2+1\geq 0 \iff 465n^3-6n^4-10n^2\geq -1\\\iff n^2(465n-6n^2-10)\geq -1$

Observe that, because $n \geq 2$ and is an integer,

$n^2(465n-6n^2-10)\geq -1 \iff 465n-6n^2-10 \geq 0 \iff n(465-6n) \geq 10\\\iff 465-6n \geq 0 \iff n \leq \frac{465}{6}=\frac{155}{2}=77.5$

In concusion, the statement is true if and only if n is a non negative integer such that $n\leq 77$

So, 78 is the smallest value of n that does not satisfy the inequality.

Note: If you compute $(4n)^4- \sum^{n}_{i=0} (2i)^4$ for 77 and 78 you will obtain:

$(4n)^4- \sum^{n}_{i=0} (2i)^4=53810064$

$(4n)^4- \sum^{n}_{i=0} (2i)^4=-61754992$

7 0

3 years ago

If f(x) = 0, what is x? 0 only –6 only –2, 1, or 3 only –6, –2, 1, or 3 only

Angelina_Jolie [31]

Answer:

answer will be 0

plz mark me as brainliest

8 0

2 years ago

Plzzz help asap this is due and plz tell me why and how to do this

Ilia_Sergeevich [38]

F - Irrational, -13.8
Because the negative sign is not inside of the radical, we can tell that the number is being multiplied by the negative. Thus, do the radical equation first, get the answer 13.8202... and multiply by -1 to get the answer. Also, it is irrational because it is not a perfect square.

6 0

3 years ago