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3 years ago

What is 78% of $350 what do you have to do to get this answer to the question

Mathematics

2 answers:

g100num [7]3 years ago

8 0

Set up the problem as a ratio:
78 x
----- = ----
100 350

100x = 27,300
x = 273

$273.00

max2010maxim [7]3 years ago

7 0

Hope I helped :)......

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3 years ago

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olga55 [171]

Answer:

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2 years ago

Evaluate the expression when x = –12. 3x – 17 a. –53 b. –19 c. 19 d. 53

Angelina_Jolie [31]

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3 years ago

The average value of a function f over the interval [−2,3] is −6 , and the average value of f over the interval [3,5] is 20. Wha

Xelga [282]

Answer:

The average value of $f$ over the interval $[-2,5]$ is $\frac{10}{7}$ .

Step-by-step explanation:

Let suppose that function $f$ is continuous and integrable in the given intervals, by integral definition of average we have that:

$\frac{1}{3-(-2)} \int\limits^{3}_{-2} {f(x)} \, dx = -6$ (1)

$\frac{1}{5-3} \int\limits^{5}_{3} {f(x)} \, dx = 20$ (2)

By Fundamental Theorems of Calculus we expand both expressions:

$\frac{F(3)-F(-2)}{3-(-2)} = -6$

$F(3) - F(-2) = -30$ (1b)

$\frac{F(5)-F(3)}{5-3} = 20$

$F(5) - F(3) = 40$ (2b)

We obtain the average value of $f$ over the interval $[-2, 5]$ by algebraic handling:

$F(5) - F(3) +[F(3)-F(-2)] = 40 + (-30)$

$F(5) - F(-2) = 10$

$\frac{F(5)-F(-2)}{5-(-2)} = \frac{10}{5-(-2)}$

$\bar f = \frac{10}{7}$

The average value of $f$ over the interval $[-2,5]$ is $\frac{10}{7}$ .

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2 years ago

GI bisects DGH so that m DGI is x-3 and mIGH is 2x-13 find the value of x

baherus [9]

x = 10

since GI bisects ∠DGH then ∠DGI = ∠IGH, hence

2x - 13 = x - 3 ( subtract x from both sides )

x - 13 = - 3 ( add 13 to both sides )

x = 10

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2 years ago

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