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3 years ago

What acronym is used for sine , cosine and tangent

Mathematics

1 answer:

sergejj [24]3 years ago

8 0

Answer:

SOHCAHTOA.

Step-by-step explanation:

acronym is an abbreviation formed from the initial letters of other words and pronounced as a word

The acronym for sin cosine and tangent is

SOHCAHTOA

Sine =Opposite over Hypotenuse

Cosine= Adjacent over Hypotenuse

Tangent= Opposite over Adjacent

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Please help ASAP. The picture is above

Setler [38]

Every triangle’s inner angles’ addition equals to 180°
So if we find the x:
38°+x+2°+x=180°
40°+2x=180°
2x=180°-40°=140°
x=140°/2
x=70°
Now if we find the I hope this helped :)

7 0

3 years ago

Read 2 more answers

Which of the following is not one of the 8th roots of unity?

Anika [276]

Answer:

1+i

Step-by-step explanation:

To find the 8th roots of unity, you have to find the trigonometric form of unity.

1. Since $z=1=1+0\cdot i,$ then

$Rez=1,\\ \\Im z=0$

and

$|z|=\sqrt{1^2+0^2}=1,\\ \\\\\cos\varphi =\dfrac{Rez}{|z|}=\dfrac{1}{1}=1,\\ \\\sin\varphi =\dfrac{Imz}{|z|}=\dfrac{0}{1}=0.$

This gives you $\varphi=0.$

Thus,

$z=1\cdot(\cos 0+i\sin 0).$

2. The 8th roots can be calculated using following formula:

$\sqrt[8]{z}=\{\sqrt[8]{|z|} (\cos\dfrac{\varphi+2\pi k}{8}+i\sin \dfrac{\varphi+2\pi k}{8}), k=0,\ 1,\dots,7\}.$

Now

at k=0, $z_0=\sqrt[8]{1} (\cos\dfrac{0+2\pi \cdot 0}{8}+i\sin \dfrac{0+2\pi \cdot 0}{8})=1\cdot (1+0\cdot i)=1;$

at k=1, $z_1=\sqrt[8]{1} (\cos\dfrac{0+2\pi \cdot 1}{8}+i\sin \dfrac{0+2\pi \cdot 1}{8})=1\cdot (\dfrac{\sqrt{2}}{2}+i\dfrac{\sqrt{2}}{2})=\dfrac{\sqrt{2}}{2}+i\dfrac{\sqrt{2}}{2};$

at k=2, $z_2=\sqrt[8]{1} (\cos\dfrac{0+2\pi \cdot 2}{8}+i\sin \dfrac{0+2\pi \cdot 2}{8})=1\cdot (0+1\cdot i)=i;$

at k=3, $z_3=\sqrt[8]{1} (\cos\dfrac{0+2\pi \cdot 3}{8}+i\sin \dfrac{0+2\pi \cdot 3}{8})=1\cdot (-\dfrac{\sqrt{2}}{2}+i\dfrac{\sqrt{2}}{2})=-\dfrac{\sqrt{2}}{2}+i\dfrac{\sqrt{2}}{2};$

at k=4, $z_4=\sqrt[8]{1} (\cos\dfrac{0+2\pi \cdot 4}{8}+i\sin \dfrac{0+2\pi \cdot 4}{8})=1\cdot (-1+0\cdot i)=-1;$

at k=5, $z_5=\sqrt[8]{1} (\cos\dfrac{0+2\pi \cdot 5}{8}+i\sin \dfrac{0+2\pi \cdot 5}{8})=1\cdot (-\dfrac{\sqrt{2}}{2}-i\dfrac{\sqrt{2}}{2})=-\dfrac{\sqrt{2}}{2}-i\dfrac{\sqrt{2}}{2};$

at k=6, $z_6=\sqrt[8]{1} (\cos\dfrac{0+2\pi \cdot 6}{8}+i\sin \dfrac{0+2\pi \cdot 6}{8})=1\cdot (0-1\cdot i)=-i;$

at k=7, $z_7=\sqrt[8]{1} (\cos\dfrac{0+2\pi \cdot 7}{8}+i\sin \dfrac{0+2\pi \cdot 7}{8})=1\cdot (\dfrac{\sqrt{2}}{2}-i\dfrac{\sqrt{2}}{2})=\dfrac{\sqrt{2}}{2}-i\dfrac{\sqrt{2}}{2};$

The 8th roots are

$\{1,\ \dfrac{\sqrt{2}}{2}+i\dfrac{\sqrt{2}}{2},\ i, -\dfrac{\sqrt{2}}{2}+i\dfrac{\sqrt{2}}{2},\ -1, -\dfrac{\sqrt{2}}{2}-i\dfrac{\sqrt{2}}{2},\ -i,\ \dfrac{\sqrt{2}}{2}-i\dfrac{\sqrt{2}}{2}\}.$

Option C is icncorrect.

5 0

3 years ago

Answer this pls pls pls pls pls

Black_prince [1.1K]

Answer:

The last one

Step-by-step explanation:

f(2) = 4x-5 = 3

f(-4) = 4x - 5 = -21

F(2) has a greater value than f(-4)

6 0

3 years ago

Please help me this is due today

Serjik [45]

Answer:

1. 15 (A)

2. 12 (G)

Step-by-step explanation:

1. We can make an equation out of this...

3x+3=48

x is the age of Geoff which is what we are trying to find out

We have to add 3 to both sides of the equation

3x+3=48

-3 -3

________

we end up with 3x=45

we then have to divide 3 by both sides because its the opposite of

multipling

3x=45

_____

we get x=15

2. We can write a problem statement

(2 x 9)-6=?

multiply 2 and 9 <u>FIRST</u>

18-6=?

your answer is 12

Your Welcome! Have a great rest of your day! :)

7 0

3 years ago

For a scavenger hunt, Jim's mom distributed a bag of 440 jelly beans evenly into 20 plastic containers and hid them around the y

natulia [17]

Answer: 11

Step-by-step explanation:

Given

Jim's mom distributed a bag of 440 Jelly beans evenly in to 20 Plastic bags

i.e.each bag has $\frac{440}{20}=22$ Jelly.

After the hunt, Jim has 242 Jelly. This much Jelly constitutes

$\Rightarrow \dfrac{242}{22}=11\ \text{bags}$

Therefore, Jim has 11 bags of Jellys

6 0

3 years ago