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3 years ago

15

A piston is seated at the top of a cylindrical chamber with radius 5 cm when it starts moving into the chamber at a constant spe

ed of 3 cm/s. What is the rate of change of the volume of the cylinder when the piston is 2 cm from the base of the chamber?

1 answer:

Tanzania [10]3 years ago

6 0

Rate is change is 1.2

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1 year ago

Im Confused… <br><br> ( The question is in the image )

erma4kov [3.2K]

Answer:

488

Step-by-step explanation:

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2 years ago

A grocery store sells salmon fillets in package that contains at least 3 fillets of salmon,but no more than 5.which of the follo

34kurt

Answer: 18 ≤ 6*S ≤ 30

Where S is the number of salmon fillets in one single package.

Step-by-step explanation:

Let's define S as the number of salmon fillets in one package.

We know that it contains at least 3, and no more than 5, then we can write:

3 ≤ S ≤ 5

Now we want to know the total number of salmon fillets that could be on 6 packages, then if S is the number of salmon fillets in one package, 6*S will e the number of salmon fillets in 6 packages.

We can find this by multiplying the inequality:

3 ≤ S ≤ 5

by 6.

We get:

6*3 ≤ 6*S ≤ 6*5

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Then in 6 packages, we could have any number between 18 and 30 fillets of salmon.

8 0

3 years ago

Log(x⁴+3x³) - log(X + 3 ) + log2 - log6 = 2logx . find the value of x

AfilCa [17]

The given equation is

$\begin{gathered} \log (x^4+3x^3)-\log (x+3)+\log 2-\log 6=2\log x \\ \log (\frac{x^4+3x^{3^{}}}{x+3})+\log \frac{2}{6}=\log x^2 \\ \log \frac{x^3(x+3)}{x+3}+\log \frac{1}{3}=\log x^2 \\ \log x^3+\log \frac{1}{3}=\log x^2 \\ \log \frac{x^3}{3}=\log x^2 \\ \frac{x^3}{3}=x^2 \\ x^3-3x^2=0 \\ x^2(x-3)=0 \end{gathered}$

hence

$x=0\text{ or x=3}$

But x cannot be zero so x=3

So the value of x is 3

h

7 0

1 year ago

PLEASE HELP For a particular transformer, the voltage E in the circuits is related to the number of windings W of wire around t

Masja [62]

Answer:

A voltage of 760V will be produced by 19 windings.

Step-by-step explanation:

Given the equation:

E = 40W

Where E is the Voltage in the circuits

and W is the number of windings

<u>Given</u> that E = 760V

<u>To find:</u> W = ?

<u>Solution:</u> Here, we have the given equation in 2 variables where value of 1 variable is given so other can be easily calculated by putting the value of given variable in the equation.

So, Putting the value of E in the given formula and finding W, the number of windings:

$760=40 \times W\\\Rightarrow W = \dfrac{760}{40}\\\Rightarrow W = \dfrac{76}{4}\\\Rightarrow W = 19$

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A voltage of 760V will be produced by 19 windings.

5 0

3 years ago