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Firdavs [7]
4 years ago
15

A piston is seated at the top of a cylindrical chamber with radius 5 cm when it starts moving into the chamber at a constant spe

ed of 3 cm/s. What is the rate of change of the volume of the cylinder when the piston is 2 cm from the base of the chamber?
Mathematics
1 answer:
Tanzania [10]4 years ago
6 0
Rate is change is 1.2
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Answer:

Step-by-step explanation:

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4 years ago
( 7x + 1/2) + ( 7x - 7 and 1/2) Simplify
pishuonlain [190]

Answer:

The answer will be 7(2x - 1)

Step-by-step explanation:

1) Convert 7 and 1/2 to improper fraction. Use this rule: a b/c = ac + b/c

7x +  \frac{1}{2}  + 7x -  \frac{7 \times 2 + 1}{2}

2) Simplify 7 × 2 to 14 .

7x +  \frac{1}{2}  + 7x  -  \frac{14 + 1}{2}

3) Simplify 14 + 1 to 15.

7x +  \frac{1}{2}  + 7x -  \frac{15}{2}

4) Collect like terms.

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5) simplify.

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6) Factor out the common term 7.

7(2x - 1)

Therefor, the answer is 7( 2x - 1 ).

7 0
3 years ago
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IrinaVladis [17]

Answer:

45x + 180 = - 720

Step-by-step explanation:

Let the required number be x.

Therefore, product of 45 and x = 45x

180 added to 45x = 45x + 180

Since, 180 Added to the product of 45 and a number totals negative 720.

So, 45x + 180 = - 720

6 0
3 years ago
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