If we convert the given in its mathematical form, we have,
(30x⁶/14y⁵)(7y²/6x⁴)
It can be observed that the numerator of the first and the denominator of the second have a common factor of 6x⁴. Also, the denominator of the first and the numerator of the second expression have a common factor of 7y².
((6x⁴)(5x²)/(7y²)(2y³))(7y²/6x⁴)
Cancellation of the common terms will give us an answer of,
<em>5x²/2y³
</em><em />Therefore, the simplified version of the involved operation is 5x²/2y³. <em>
</em>
Answer:
x=11
Step-by-step explanation:
For extra help the second answer is: 7a(3-a)
Answer: False.
Step-by-step explanation:
There does not exist a "quarter circle" as a circle with a radius of 4 units, the only notable circle that does exist is the unit circle, that is the circle where the radius is equal to 1, represented by the equatin x^2 + y^2 = 1
The term "quarter circle" actually does refer to a fourth part of a circle, not to a circle of radius 4.
So the statement is false
Answer:
60
Step-by-step explanation:
