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3 years ago

5

At a grocery store, each pound of apples costs $1.35. Micah finds that his bag of apples weighs 1.9 pounds. How much does the ba

g of apples cost? Label your answer and round correctly

1 answer:

Rina8888 [55]3 years ago

8 0

Answer:

Step-by-step explanation:

You can solve this using algebra and cross multiplication.

($1.65/1 lb)=(x/3.2 lbs)

x(1 lb)=($1.65)*(3.2 lbs)

x (1 lb)=5.28

x=$5.28

They will cost $5.28.

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1.Do examples that support a conjecture prove the conjecture to be true?

Fofino [41]

Answer:

A conjecture is an “educated guess” that is based on examples in a pattern. ... However, no number of examples can actually prove a conjecture. It is always possible that the next example would show that the conjecture is false. A counterexample is an example that disproves a conjecture.

8 0

4 years ago

Obesity is a risk factor for many health problems such as type 2 diabetes, high blood pressure, joint problems, and gallstones.

kodGreya [7K]

Answer:

a. A point estimate of the BMI for adults in the United States can be calculated from the sample mean, which has a value M=44.57.

b. The sample standard deviation is s=79.9507.

c. The 95% confidence interval for the BMI of adults in the United States is (26.18, 62.96).

Step-by-step explanation:

We start by calculating the sample mean and standard deviation of the BMI data:

$M=\dfrac{1}{n}\sum_{i=1}^n\,x_i\\\\\\M=\dfrac{1}{75}(16.2+31.1+24.8+. . .+22.9)\\\\\\M=\dfrac{3343}{75}\\\\\\M=44.57\\\\\\s=\sqrt{\dfrac{1}{n-1}\sum_{i=1}^n\,(x_i-M)^2}\\\\\\s=\sqrt{\dfrac{1}{74}((16.2-44.57)^2+(31.1-44.57)^2+(24.8-44.57)^2+. . . +(22.9-44.57)^2)}\\\\\\s=\sqrt{\dfrac{473016.8667}{74}}\\\\\\s=\sqrt{6392.1198}=79.9507\\\\\\$

We have to calculate a 95% confidence interval for the mean.

The population standard deviation is not known, so we have to estimate it from the sample standard deviation and use a t-students distribution to calculate the critical value.

The sample mean is M=44.57.

The sample size is N=75.

When σ is not known, s divided by the square root of N is used as an estimate of σM:

$s_M=\dfrac{s}{\sqrt{N}}=\dfrac{79.9507}{\sqrt{75}}=\dfrac{79.9507}{8.66}=9.232$

The degrees of freedom for this sample size are:

$df=n-1=75-1=74$

The t-value for a 95% confidence interval and 74 degrees of freedom is t=1.993.

The margin of error (MOE) can be calculated as:

$MOE=t\cdot s_M=1.993 \cdot 9.232=18.39$

Then, the lower and upper bounds of the confidence interval are:

$LL=M-t \cdot s_M = 44.57-18.39=26.18\\\\UL=M+t \cdot s_M = 44.57+18.39=62.96$

The 95% confidence interval for the BMI of adults in the United States is (26.18, 62.96).

4 0

4 years ago

Someone help please this is for corrections

nlexa [21]

Answer:

5.25

Step-by-step explanation:

there are 12 people- $21/ per person you will divide 4 into 21 your answer should be 5.25

8 0

3 years ago

Solve the proportion of 16/50=x/156.25

Dmitrij [34]

Do cross multiplication
50x=16*156.25
50x =2500
X= 50

3 0

3 years ago

Read 2 more answers

Suppose that vehicles taking a particular freeway exit can turn right (R), turn left (L), or go straight (S). Consider observing

Basile [38]

Answer:

a)

A={RRR,SSS,LLL}

b)

B={RSL,SLR,LRS,RLS,SRL,LSR}

c)

C={RRL,RLR,LRR,RRS,SRR,RSR}

d)

D={RRL, RRS, RLR, RLL, RSR, RSS, LRR, LRL, LLR, LLS, LSL, LSS, SRR, SRS, SLL, SLS, SSR, SSL}

e)

D'={RRR, RLS, RSL, LRS, LLL, LSR, SRL, SLR, SSS}

Step-by-step explanation:

Sample space=S= {RRR, RRL, RRS, RLR, RLL, RLS, RSR, RSL, RSS, LRR, LRL, LRS, LLR, LLL, LLS, LSR, LSL, LSS, SRR, SRL, SRS, SLR, SLL, SLS, SSR, SSL, SSS}

a)

Let A be the event that all three vehicles go in same direction. It means that the all three vehicles go to right or left or straight. Thus, event A can be represented as

A={RRR,SSS,LLL}

b)

Let B be the event that all three vehicles go in different direction. It means that the three vehicles can go to

1. Right, Straight, Left

2. Straight, Left, Right

3. Left, Right, Straight

4. Right, Left, Straight

5. Straight, Right, Left

6. Left, Straight, Right

Thus, event B can be represented as

B={RSL,SLR,LRS,RLS,SRL,LSR}

c)

Let C be the event that exactly two of three vehicles turn right. It means that the three vehicles can go to

1. Right, Right , Left

2. Right , Left, Right

3. Left, Right, Right

4. Right, Right , Straight

5. Straight, Right,Right

6. Right , Straight, Right

Thus, event C can be represented as

C={RRL,RLR,LRR,RRS,SRR,RSR}

d)

Let D be the event that exactly two of three vehicles go in same direction. It means that the three vehicles can go to

1. Right, Right, Left

2. Right, Right, Straight

3. Right, Left, Right

4. Right, Left, Left

5. Right, Straight, Right

6. Right, Straight, Straight

7. Left, Right, Right

8. Left, Right, Left

9. Left, Left, Right

10. Left, Left, Straight

11. Left, Straight, Left

12. Left, Straight, Straight

13. Straight, Right, Right

14. Straight, Right, Straight

15. Straight, Left, Left

16. Straight, Left, Straight

17. Straight, Straight, Right

18.Straight,Straight, Left

Thus, event D can be represented as

D={RRL, RRS, RLR, RLL, RSR, RSS, LRR, LRL, LLR, LLS, LSL, LSS, SRR, SRS, SLL, SLS, SSR, SSL}

e)

D'=S-D= {RRR, RRL, RRS, RLR, RLL, RLS, RSR, RSL, RSS, LRR, LRL, LRS, LLR, LLL, LLS, LSR, LSL, LSS, SRR, SRL, SRS, SLR, SLL, SLS, SSR, SSL, SSS} -{RRL, RRS, RLR, RLL, RSR, RSS, LRR, LRL, LLR, LLS, LSL, LSS, SRR, SRS, SLL, SLS, SSR, SSL}

D'={RRR, RLS, RSL, LRS, LLL, LSR, SRL, SLR, SSS}

8 0

3 years ago