Answer:
<u>252 square inches is the surface area of Josiah's cereal box.</u>
Step-by-step explanation:
1. Let's review the information given to us to answer the question correctly:
Height of the box = 11 inches
Length of the box = 8 inches
Width of the box = 2 inches
2. What is the surface area of Josiah's cereal box?
Let's recall the surface area of a rectangular prism:
Surface area = 2 (width * length + height * width + length * height)
Surface area = 2 (2 * 8 + 11 * 2 + 8 * 11)
Surface area = 2 (16 + 22 + 88)
Surface area = 2 * 126
<u>Surface area = 252 inches²</u>
Answer:
g = 
Step-by-step explanation:
Given that g varies inversely as h³ then the equation relating them is
g = ← k is the constant of variation
I believe A is the correct answer
Answer:
maximum height is 4.058 metres
Time in air = 0.033 second
Step-by-step explanation:
Given that the equation height h
h = -212t^2 + 7t + 4
What is the toy's maximum height?
Let us assume that the equation is a perfect parabola
Time t at Maximum height will be
t = -b/2a
Where b = 7 and a = - 212
t = -7/ - 212 ×2
t = 7/ 424 = 0.0165s
Substitute t in the main equation
h = - 212(7/424)^2 + 7(7/424) + 4
h = - 0.05778 + 0.115567 + 4
h = 4.058 metres
Therefore the maximum height is 4.058 metres
How long is the toy in the air?
The object will go up and return to the ground.
At ground level, h = 0
-212t^2 + 7t + 4 = 0
212t^2 - 7t - 4 = 0
You can factorize the above equation and pick the positive time t since time can't be negative
Or
Since we have assumed that it's a perfect parabola,
Total time in air = (-b/2a) × 2
Time in air = 0.0165 × 2 = 0.033 s
Part A:
I have attached the graph of this system of inequalities.
Part B:
Plug in (8,10) into both equations
10 > 3(8) + 10
10 > 24 + 10
10 > 34
This is false!
10 < (-3/4)(8) - 1
10 < (-3)(2) - 1
10 < -6 - 1
10 < -7
This is also false!
So,
(8,10) is not included in the solution area for the system.
