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Maksim231197 [3]
3 years ago
5

Use the quadratic formula to si 3x2 + 8x – 4= 0

Mathematics
1 answer:
omeli [17]3 years ago
3 0

Answer:

\large\boxed{x=\dfrac{-4-2\sqrt7}{3}\ or\ x=\dfrac{-4+2\sqrt7}{3}}

Step-by-step explanation:

\text{The quadratic formula for a quadratic equation}\ ax^2+bx+c=0\\\\\text{determinant:}\ \Delta=b^2-4ac\\\\\text{If}\ \Delta0,\ \text{then the equation has two different solutions}\ x=\dfrac{-b\pm\sqrt\Delta}{2a}.

\text{We have:}\\\\3x^2+8x-4=0\\\\a=3,\ b=8,\ c=-4\\\\\Delta=8^2-4(3)(-4)=64+48=112>0\\\sqrt\Delta=\sqrt{112}=\sqrt{(16)(7)}=\sqrt{16}\cdot\sqrt7=4\sqrt7\\\\x=\dfrac{-8\pm4\sqrt7}{2(3)}=\dfrac{-8\pm4\sqrt7}{6}=\dfrac{2(-4\pm2\sqrt7)}{6}=\dfrac{-4\pm2\sqrt7}{3}

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Indicate the answer choice that best completes the statement or answers the question.
Tema [17]

Answer:

C

Step-by-step explanation:

m<2:

180 - 60 - 48 = 72

Vertical angle thm:

m<1 = 48

m<3:

180 - 62 - 48 = 70

6 0
3 years ago
1. an alloy contains zinc and copper in the ratio of 7:9 find weight of copper of it had 31.5 kgs of zinc.
m_a_m_a [10]

Answer:

Step-by-step explanation:

Question (1). An alloy contains zinc and copper in the ratio of 7 : 9.

If the weight of an alloy = x kgs

Then weight of copper = \frac{9}{7+9}\times (x)

                                      = \frac{9}{16}\times (x)

And the weight of zinc = \frac{7}{7+9}\times (x)

                                      = \frac{7}{16}\times (x)

If the weight of zinc = 31.5 kg

31.5 = \frac{7}{16}\times (x)

x = \frac{16\times 31.5}{7}

x = 72 kgs

Therefore, weight of copper = \frac{9}{16}\times (72)

                                               = 40.5 kgs

2). i). 2 : 3 = \frac{2}{3}

        4 : 5 = \frac{4}{5}

Now we will equalize the denominators of each fraction to compare the ratios.

\frac{2}{3}\times \frac{5}{5} = \frac{10}{15}

\frac{4}{5}\times \frac{3}{3}=\frac{12}{15}

Since, \frac{12}{15}>\frac{10}{15}

Therefore, 4 : 5 > 2 : 3

ii). 11 : 19 = \frac{11}{19}

    19 : 21 = \frac{19}{21}

By equalizing denominators of the given fractions,

\frac{11}{19}\times \frac{21}{21}=\frac{231}{399}

And \frac{19}{21}\times \frac{19}{19}=\frac{361}{399}

Since, \frac{361}{399}>\frac{231}{399}

Therefore, 19 : 21 > 11 : 19

iii). \frac{1}{2}:\frac{1}{3}=\frac{1}{2}\times \frac{3}{1}

             =\frac{3}{2}

     \frac{1}{3}:\frac{1}{4}=\frac{1}{3}\times \frac{4}{1}

              = \frac{4}{3}

Now we equalize the denominators of the fractions,

\frac{3}{2}\times \frac{3}{3}=\frac{9}{6}

And \frac{4}{3}\times \frac{2}{2}=\frac{8}{6}

Since \frac{9}{6}>\frac{8}{6}

Therefore, \frac{1}{2}:\frac{1}{3}>\frac{1}{3}:\frac{1}{4} will be the answer.

IV). 1\frac{1}{5}:1\frac{1}{3}=\frac{6}{5}:\frac{4}{3}

                  =\frac{6}{5}\times \frac{3}{4}

                  =\frac{18}{20}

                  =\frac{9}{10}

Similarly, \frac{2}{5}:\frac{3}{2}=\frac{2}{5}\times \frac{2}{3}

                       =\frac{4}{15}                  

By equalizing the denominators,

\frac{9}{10}\times \frac{30}{30}=\frac{270}{300}

Similarly, \frac{4}{15}\times \frac{20}{20}=\frac{80}{300}

Since \frac{270}{300}>\frac{80}{300}

Therefore, 1\frac{1}{5}:1\frac{1}{3}>\frac{2}{5}:\frac{3}{2}

V). If a : b = 6 : 5

     \frac{a}{b}=\frac{6}{5}

        =\frac{6}{5}\times \frac{2}{2}

        =\frac{12}{10}

  And b : c = 10 : 9

  \frac{b}{c}=\frac{10}{9}

 Since a : b = 12 : 10

 And b : c = 10 : 9

 Since b = 10 is common in both the ratios,

 Therefore, combined form of the ratios will be,

 a : b : c = 12 : 10 : 9

7 0
3 years ago
Add 34+(−212) using the number line. Select the location on the number line to plot the sum.
nexus9112 [7]

Answer:

-1 3/4

Step-by-step explanation:

3/4 + (-2 1/2)

3/4 - 2

-1 3/4

5 0
3 years ago
PLEASE HELP SOON! ALSO INCLUDE A SMALL EXPLANATION as well as the answer ! I am rewarding 100points if you answer quickly
alina1380 [7]

Answer:

the answer is B

f(x)=-2x+3

Step-by-step explanation:

to get the -2x I did --->

pick two points I used (0,3) and (1,1) and used the equation \frac{y2-y1}{x2-x1}

where y2 would be 1 and y1 would be 3

and where x2 would be 1 and x1 would be 0

so you would put the numbers in the equation which would look like\frac{1-3}{1-0}=\frac{-2}{1} and equal -2 which would be -2x in the answer

And the +3 is the y-intercept

4 0
3 years ago
Read 2 more answers
Math help ( 20 pts )
Nimfa-mama [501]
A) The answer is 24 m

x - the distance from the spot on the beach to the parking lot

Triangles that are divided by x distance is similar, and therefore:
x : 18 = 32 : x
x * x = 18 * 32
x² = 576
x = √576
x = 24

Thus, the distance <span>the spot on the beach from the parking lot is 24 m.
</span>

b) The answer is 40 m.

x - the distance from the spot on the beach to the parking lot
b - distance from the parking lot to the refreshment stand.

First, find the horizontal leg (a) of the biggest right triangle. According to the Pythagorean theorem:
a² + b² = c²
a = ?
b = ?
c = 32 m + 18 m = 50 m

Find a from the right triangle which sides are a (as a hypotenuse), x, and 18 m.
x² + 18² = a²
x = 24
24² + 18² = a²
576 + 324 = a²
900 = a²
a = √900
a = 30 m

Now, find b:
a² + b² = c²
30² + b² = 50²
900 + b² = 2500
b² = 2500 - 900
b² = 1600
b = √1600
b = 40 m

Thus the distance from the parking lot to get the refreshment stand is 40 m.
6 0
3 years ago
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