What is the side length of the smallest square plate on which a 24-cm chopstick can fit along a diagonal without any overhang?
1 answer:
Answer:
17 cm is the side length of the smallest square plate.
Step-by-step explanation:
Length of the square = l
Length of the diagonal = d
Length of chopstick = s = 24 cm
If chopstick is to be fitted along a diagonal . then length of the diagonal will be:
d = s = 24 cm
Applying Pythagoras Theorem :
17 cm is the side length of the smallest square plate.
You might be interested in
Answer:
To give more clarity to the question, lets examine the attached back-to-back stem plot.
A)
Having examined the stem plot, we can using quick calculations, summarize that:
The mean (40.45 cal/kg) and median (41 cal/kg) daily caloric intake of ninth-grade students in the rural school is higher than the corresponding measures of center, mean (32.6 cal/kg) and median (32 cal/kg), for ninth-graders in the urban school.
The median and the mean for the students in the 9th grade in the urban school is lower than that of those of their contemporaries in the rural school. The respective medians and means are stated below:
Urban 9th Grade Students
Median = 32 cal/kg
Mean = 36 cal/kg
Rural 9th Grade Students
Median = 41 cal/kg
Mean = 41 cal/kg
Please note that all figures above have been approximated to the nearest whole number.
B)
It is unreasonable to generalize the findings of this study to all rural and urban 9th-grade students in the United States because the sample is too small compared to the target population size.
To allow for generalization, they would have to collect and analyze more samples say from every state within America.
Cheers!
I assume the first equation is supposed to be
and not
As an augmented matrix, this system is given by
Multiply through row 3 by 1/2:
Add -1(row 2) to row 3:
Multiply through row 3 by 1/5:
Add -2(row 3) to row 1, and add 3(row 3) to row 2:
Add -3(row 2) to row 1:
Multiply through row 1 by -1:
Add -2(row 1) to row 2:
Multipy through row 2 by -1:
The solution to the system is then
Explanation:
1. CS ≅ HR, ∠CHS ≅ ∠HCR, ∠CSH ≅ ∠HRC — given
2. ∆CRH ~ ∆HSC — AA similarity theorem
3. ∠SCH ≅ ∠RHC — corresponding angles of similar triangles are congruent
4. CH ≅ HC — reflexive property of congruence
5. ∆CRH ≅ ∆HSC — SAS congruence theorem
6. CR ≅ HS — CPCTC
