Answer:
16.
Hope this helps, have a great day/night!
Answer:
Horizontal asymptote of the graph of the function f(x) = 16x/(3+x^2) is y=0
Step-by-step explanation:
I attached the graph of the function. Graphically it can be seen that the horizontal asymptote of the graph of the function is y=0.
When denominator's degree (2) is higher than nominator's degree (1) then the horizontal asymptote is y=0
Answer:
10 is the distance
Step-by-step explanation:
d = square root (x2-x1)^2 + (y2-y1)^2
(5-5)^2 = 0
(2-(-8))^2 = 100
0 + 100 = 100
square root 100 = 10