In Exercise,find the horizontal asymptote of the graph of the function. f(x) = 16x/3+x^2
1 answer:
Answer:
Horizontal asymptote of the graph of the function f(x) = 16x/(3+x^2) is y=0
Step-by-step explanation:
I attached the graph of the function. Graphically it can be seen that the horizontal asymptote of the graph of the function is y=0.
When denominator's degree (2) is higher than nominator's degree (1) then the horizontal asymptote is y=0
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Answer:
see below
Step-by-step explanation:
Corresponding letters (vertices) are in the same order in the similarity statement. That is, if L is the first letter in ∆LMN, then it corresponds to the first letter (R) in ∆RST. That is the meaning of ∆LMN ~ ∆RST.
3. Everywhere you see L, replace it with R.
Everywhere you see M, replace it with S.
Everywhere you see N, replace it with T.
This goes for both segments and angles.
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4. Everywhere you see A, replace it with H.
Everywhere you see B, replace it with G.
Everywhere you see C, replace it with F.
Everywhere you see D, replace it with E.
This goes for both segments and angles.
