In Exercise,find the horizontal asymptote of the graph of the function. f(x) = 16x/3+x^2
1 answer:
Answer:
Horizontal asymptote of the graph of the function f(x) = 16x/(3+x^2) is y=0
Step-by-step explanation:
I attached the graph of the function. Graphically it can be seen that the horizontal asymptote of the graph of the function is y=0.
When denominator's degree (2) is higher than nominator's degree (1) then the horizontal asymptote is y=0
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Answer:
Step-by-step explanation:
Quadratic function-
It is a function that can be represented by an equation of the form , where
In a quadratic function, the greatest power of the variable is 2.
As in the first option the highest power is 3, so it is not a quadratic function.
Even though the power of x is 2 in the third option, but as it is in the denominator, so the overall power of x becomes -2. Hence it is not a quadratic function.
As the coefficient of is 0 in case of fourth option, so it is not a quadratic function.
Equation in option 2 satisfies all the conditions of quadratic function, hence it is the quadratic function.
For the given triangle, the value of x equals 30.9892 units.
Step-by-step explanation:
Step 1:
In the triangle, the angle is 40°, the opposite side has a length of 26 units, the adjacent side has a length of x units while the hypotenuse is not given.
To determine the value of x, we determine the value of the tan of the given triangle.
To calculate the tan of angle A we divide the opposite side's length by the the adjacent side's length.
Step 2:
The length of the opposite side = 26 units.
The length of the adjacent side = x units.
So x measures 30.9892 units.