Complete question is attached.
Answer:
B) 8
Step-by-step explanation:
In this question, KLMN ~ PQRS. This means they are similar shapes.
From the image, we could denote that:
KL ~ PQ
LM ~ QR
Given that:
KL = 12
PQ = 30
QR = 20
LM = x
To find x, let's use tge expression:
Cross multiplying, we have:
12 * 20 = 30x
240 = 30x
To find x, let's divide both sides by 30.
8 = x
x = 8
The correct option is option B.
Answer: Your answers ×=5 !
Answer:
P(cell has at least one of the positive nickel-charged options) = 0.83.
P(a cell is not composed of a positive nickel charge greater than +3) = 0.85.
Step-by-step explanation:
It is given that the Nickel Charge Proportions found in the battery are:
0 ==> 0.17
.
+2 ==> 0.35
.
+3 ==> 0.33
.
+4 ==> 0.15.
The numbers associated to the charge are actually the probabilities of the charges because nickel is an element that has multiple oxidation states that is usually found in the above mentioned states.
a) P(cell has at least one of the positive nickel-charged options) = P(a cell has +2 nickel-charged options) + P(a cell has +3 nickel-charged options) + P(a cell has +4 nickel-charged options) = 0.35 + 0.33 + 0.15 = 0.83.
Or:
P(a cell has at least one of the positive nickel-charged options) = 1 - P(a cell has 0 nickel-charged options) = 1 - 0.17 = 0.83.
b) P(a cell is not composed of a positive nickel charge greater than +3) = 1 - P(a cell is composed of a positive nickel charge greater than +3)
= 1 - P(a cell has +4 nickel-charged options) '.' because +4 is only positive nickel charge greater than +3
= 1 - 0.15
= 0.85
To summarize:
P(cell has at least one of the positive nickel-charged options) = 0.83!!!
P(a cell is not composed of a positive nickel charge greater than +3) = 0.85!!!
Given:
First, let us find two points from this equation.
We can set values of x and then solve for y.
Let us find the values of y when x = 1, 2, 3, 4, 5
We now have a set of points:
(1, 21)
(2, 16)
(3, 11)
(4, 6)
(5, 1)
Since the given plane is limited to values of 10 and -10, the points that we can plot are the points (4, 6) and (5, 1)
The graph would then look like this:
Set each of the binomials equal to zero and solve for x. The two values will be the zeros of the equation:
(x-4) = 0 (x+11) = 0
x-4 = 0 x + 11 = 0
x = 4 x = -11
The zeros of the equation are -11 and 4
