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insens350 [35]
3 years ago
14

Helps pls :-/ number 12 any help is greatly appreciated!

Mathematics
1 answer:
Alexandra [31]3 years ago
6 0
X = 5, that’s the answer to question 12
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What is the mean of -36,-25,12,-3 and 18
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A promissory note for $3600.00 dated May 15, 2012, requires an interest payment of $370.00 at maturity. If interest is at 9.6% c
vladimir1956 [14]

The due date of the promissory note is May 24th 2013.

Data;

  • Present Value (PV) = $3600
  • Interest = $370
  • Future Value (FV) = PV + I = $3600 + $370 = $3970

<h3>Due Date of the Note</h3>

To calculate the due date of the note, we can use the formula of future value of the note.

FV = PV (1 + \frac{r}{n})^d\\ 3970 = 3600 (1 + \frac{9.6}{12})^d\\3970 = 3600(1+0.008)^d\\\frac{3970}{3600} =(1.008)^n

Let's take the natural log of both sides

(1.008)^n = (\frac{3970}{3600})\\ n\ln(1.008) = \ln(\frac{397}{360})\\ n = 12.28

This is approximately 12 months and 9 days.

The due date of the promissory note is May 24th 2013.

Learn more on promissory note here;

brainly.com/question/25793394

brainly.com/question/4267195

7 0
2 years ago
10 points for answering!<br> What is the answer to 13, 14, and 15?
ki77a [65]

Step-by-step explanation:

<h2>13. </h2>

\implies\sf{ {x}^{2} = 144 } \\  \\  \implies\sf{ x =  \pm \sqrt{144} }   \\  \\ \implies\sf{ x =  \pm 12 }

<h2>14.</h2>

\implies\sf{ {x}^{2} =  \dfrac{25}{289}  } \\  \\  \implies\sf{ x =  \pm \sqrt{ \frac{25}{289} } }   \\  \\ \implies\sf{ x =  \pm  \frac{5}{17}  }

<h2>15.</h2>

\implies\sf{ {x}^{3} = 216 } \\  \\  \implies\sf{ x =   \sqrt[3]{216}  }   \\  \\ \implies\sf{ x =  6 }

4 0
3 years ago
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