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tensa zangetsu [6.8K]
3 years ago
6

What is tan(x)= 50÷30

Mathematics
1 answer:
Contact [7]3 years ago
6 0
20 because you are doing 50-30=20 adding x so it would be 20x
You might be interested in
X+y= -9<br> x+2y= -25<br><br> According to the system of equations above, what is the value of y?
Varvara68 [4.7K]
Try this option:
if x+y=-9 is I (one)
and x+2y=-25 is II (two), then
if II-I, then (x+2y)-(x+y)=-25+9 ⇔ y=-16.
6 0
3 years ago
Consider the equation 5x^2-10x+c=0. What values of c result in the equation having a complex solutions? Represent your answer on
stiv31 [10]

Answer:

When we have a quadratic equation:

a*x^2 + b*x + c = 0

There is something called the determinant, and this is:

D = b^2 - 4*a*c

If D < 0, then the we will have complex solutions.

In our case, we have

5*x^2 - 10*x + c = 0

Then the determinant is:

D = (-10)^2 - 4*5*c = 100 - 4*5*c

And we want this to be smaller than zero, then let's find the value of c such that the determinant is exactly zero:

D = 0 = 100 - 4*5*c

    4*5*c = 100  

       20*c = 100

            c = 100/20 = 5

As c is multiplicating the negative term in the equation, if c increases, then we will have that D < 0.

This means that c must be larger than 5 if we want to have complex solutions,

c > 5.

I can not represent this in your number line, but this would be represented with a white dot in the five, that extends infinitely to the right, something like the image below:

8 0
2 years ago
Someone please help me with this!!!
Alexxx [7]
34.I
for this problem you just multiply the 20 by 2=40
and then you add 40+3=43
which will equal
\frac{43}{20}


35.G
if you divide
58 \div 25 = 2.32
so G
\frac{58}{25}

36. C
\frac{5}{5}  = 1
so if you subtract
\frac{6}{5}  -  \frac{5}{5}
will equal

\frac{1}{5}
1 \frac{1}{5}
7 0
2 years ago
Read 2 more answers
The diagonals of a trapezoid are perpendicular <br> Always <br> Sometimes <br> Never
iren [92.7K]
The correct answer is Sometimes
4 0
2 years ago
Solve for x 73 =(9/10x)+19
Yuliya22 [10]
73=(\frac{9}{10}x)+19

To solve x:

1. Substract 19 in both sides of the equation:

\begin{gathered} 73-19=(\frac{9}{10}x)+19-19 \\  \\ 54=\frac{9}{10}x \end{gathered}

2. Multiply both sides of the ewuation by 10/9:

\begin{gathered} 54\cdot\frac{10}{9}=\frac{9}{10}x\cdot\frac{10}{9} \\  \\ \frac{540}{9}=x \\  \\ 60=x \end{gathered}<h2>Then, the value of x is 60 (x=60)</h2>
3 0
7 months ago
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