Answer:
B
Step-by-step explanation:
I got this answer correct on a test
Step-by-step explanation:
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Answer:
The minimum score required for an A grade is 83.
Step-by-step explanation:
Normal Probability Distribution:
Problems of normal distributions can be solved using the z-score formula.
In a set with mean
and standard deviation
, the z-score of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.
Mean of 72.3 and a standard deviation of 8.
This means that 
Find the minimum score required for an A grade.
This is the 100 - 9 = 91th percentile, which is X when Z has a pvalue of 0.91, so X when Z = 1.34.




The minimum score required for an A grade is 83.
Given that the population has been modeled by the formula:
a=118e^(0.024t), the time taken for the population to hit 140k will be given by:
140000=118e^(0.024t)
solving for t we shall have:
140000/118=e^(0.024t)
thus;
0.024t=ln(140000/118)
t=1/0.024*ln(140000/118)
t=295
thus the time the population will be 140000 will be:
1998+295
=2293