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3 years ago

Help!!!!!!!!!!!!!!!!!!!!!!!!!!

Mathematics

2 answers:

7nadin3 [17]3 years ago

4 0

The answer is the blue one (the one your mouse is hovering over)

bekas [8.4K]3 years ago

3 0

Answer - Blue; x > 2 and x ≤ -3

Ok so one most to the left shows an arrow going "lesser" and starting at -3. Since the dot covers -3, that means it is equal to or less than -3.

So the on most to the right starts at 2 and the arrow is point "greater"

The circle is hollow, meaning is does not include 2. So that means it's greater than 2.

♡ Hope this helped! ♡

❀ 0ranges ❀

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Verdich [7]

Answer:

Find the sales (in units) needed to earn a profit of $262,500

Step-by-step explanation:

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3 years ago

Triangle JKL has vertices J(2,5), K(1,1), and L(5,2). Triangle QNP has vertices Q(-4,4), N(-3,0), and P(-7,1). Is (triangle)JKL

Tems11 [23]

Answer:

Yes they are

Step-by-step explanation:

In the triangle JKL, the sides can be calculated as following:

J(2;5); K(1;1)

=> JK = $\sqrt{(1-2)^{2} + (1-5)^{2} } = \sqrt{(-1)^{2}+(-4)^{2} } = \sqrt{1+16}=\sqrt{17}$

J(2;5); L(5;2)

=> JL = $\sqrt{(5-2)^{2} + (2-5)^{2} } = \sqrt{3^{2}+(-3)^{2} } = \sqrt{9+9}=\sqrt{18} = 3\sqrt{2}$

K(1;1); L(5;2)

=> KL = $\sqrt{(5-1)^{2} + (2-1)^{2} } = \sqrt{4^{2}+1^{2} } = \sqrt{1+16}=\sqrt{17}$

In the triangle QNP, the sides can be calculate as following:

Q(-4;4); N(-3;0)

=> QN = $\sqrt{[-3-(-4)]^{2} + (0-4)^{2} } = \sqrt{1^{2}+(-4)^{2} } = \sqrt{1+16}=\sqrt{17}$

Q (-4;4); P(-7;1)

=> QP = $\sqrt{[-7-(-4)]^{2} + (1-4)^{2} } = \sqrt{(-3)^{2}+(-3)^{2} } = \sqrt{9+9}=\sqrt{18} = 3\sqrt{2}$

N(-3;0); P(-7;1)

=> NP = $\sqrt{[-7-(-3)]^{2} + (1-0)^{2} } = \sqrt{(-4)^{2}+1^{2} } = \sqrt{16+1}=\sqrt{17}$

It can be seen that QPN and JKL have: JK = QN; JL = QP; KL = NP

=> They are congruent triangles

7 0

3 years ago

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Delicious77 [7]

Answer:

-160x+264

Step-by-step explanation:

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3 0

3 years ago

1/3k+80=1/2k+120 what does k equal?

LenaWriter [7]

Answer:

k = -1/240

Step-by-step explanation:

to evaluate the value of k in the expression 1/3k+80=1/2k+120

we have

1/3k+80=1/2k+120

collect the like terms for easy evaluation

1/3k - 1/2k = 120 -80

1/3k - 1/2k = 40

find the lcm

2 - 3/6k = 40

-1/ 6k = 40

cross multiply

6k x 40 = -1

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divide both sides by 240

240k/240 = -1/ 240

k = -1/240

therefore the value of k in the expression 1/3k+80=1/2k+120 is equals to -1/240

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3 years ago

Am gonna give branliest!!!

blagie [28]

The answer is B. -12°f

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3 years ago

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