Please please help!!!! According to the probability distribution below, what is the expected value of X? X 0 1 2 3 4 5 P(X) 0.3
0.2 0.16 0.2 0.04 0.1 A.) The expected value is 0.1 B.) The expected value is 5 C.) The expected value is 2.5 D.) The expected value is 1.78
1 answer:
Answer:
D.) The expected value is 1.78
Step-by-step explanation:
The expected value of a probability distribution is evaluated using the formula.
Expected Value, 
Therefore, from the given probability distribution, we have:
E(X)=(0*0.3)+(1*0.2)+(2*0.16)+(3*0.2)+(4*0.04)+(5*0.1)
E(X)=1.78
The Expected value of X is 1.78.
The correct option is D.
You might be interested in
Answer:
a
Step-by-step explanation:
snbxhchdjkakajiauzucucuhchxhdjdnsnananja
Answer:
7
Step-by-step explanation:
5+2=7
Even function is symmetrical about the y axis
not sure what it means if the polynomial is positive
the zeroes are how many times it hits the x axis
it hits 4 times so 4 zeros
<span>Perimeter =2w+2L= 520.
We can solve this by understanding that the area is maximized by a square
Therefore L=w.
p=2w+2w=520=4w
w=130
Area
A=wL=130(130)= 16900 square yards</span>
Answer: 40
Step-by-step explanation: