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3 years ago

6

At the beginning of a basketball season, the panthers won 40 games out of 100 games. At this rate, how many games will they win

in a normal 110-game season?

1 answer:

denis23 [38]3 years ago

7 0

At the rate of winning, they should win 44 games in normal 110-game season.

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I need help plz !!!!!!!

morpeh [17]

0: 3000

5: 500

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5 0

2 years ago

A family of five recently replaced its 5-gallon-per minute showerheads with water-saving 2-gallon per minute showerheads. Each m

lilavasa [31]

Answer:

2400 gallons of water

Step-by-step explanation:

The new shower head releases 2 gallons per minute as compared to the old type.

each person spends an average of 8 minutes in shower per day. This means each person will use 8*2 number of gallons per day.

the number of persons in the family is 5.

if 1 person uses 8*2 gallons per day, 5 people will require 8*2*5

In a 30 days period the number of gallons used by the family will be

=8*2*5*30

=2400 gallons.

3 0

3 years ago

James built a small electric car and recorded the distance it traveled. The table below shows the distance traveled (n) during t

Scrat [10]

<span>Table

Elapsed Time (seconds) Distance Traveled (feet)

1 6.2

2                                        12.4

3                                        18.6

4                                         24.8

Explanation:

You can check that 6.2 / 1 = 12.4 / 2 = 18.6 / 3 = 24.8 / 4 = 6.2

So, the relationship between the distance traveled and the time elapsed is a constant:

distance traveled / time elapsed = 6.2

n / f = 6.2

=> n = 6.2 f

Answer: n = 6.2 f
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5 0

3 years ago

Caitlin has 4 3/4 pounds of clay . She uses 1 1/10 pounds to make a cup ,and another 2 pounds to make a jar , how many pounds ar

sasho [114]

4 3/4 - 2 = 2 3/4
2 3/4 - 1 1/10 is the same as 2 30/40 - 1 4/40 = 1 26/40
1 26/40 = 1 13/20 pounds left

8 0

3 years ago

N1=731pˆ1=0. 33 n2=644pˆ2=0. 28 use this data to find the 90onfidence interval for the true difference between the population pr

postnew [5]

The 90% confidence interval for the true difference between the population proportions is [ - 0.0908, - 0.0092]

Given,

$N_{1}$ = 731

$N_{2}$ = 644

$P_{1}$ = 0.33

$P_{2}$ = 0.28

z score for 90% confidence interval = 1.645

Here, the confidence interval formula :

( $P_{1} -P_{2}$ ) ± z $\sqrt{\frac{P_{1}(1-P_{1}) }{N_{1} }+ \frac{P_{2}(1-P_{2}) }{N_{2} } }$

Substituting the values, we get

(0.33 - 0.28) ± 1.645 $\sqrt{\frac{0.33(1-0.33)}{731}+\frac{0.28(1-0.28)}{644} }$

= 0.05 ± 1.645 $\sqrt{0.0003024624+0.0003130435}$

= 0.05 ± 1.645 $\sqrt{0.0006155059}$

= 0.05 ± 1.645 × 0.0248093914

= 0. 05 ± 0.0408114489

Confidence interval:

- 0.05 - 0.0408114489 = - 0.0908114489 ≈ - 0.0908

- 0.05 + 0.0408114489 = - 0.0091885511 ≈ - 0.0092

The confidence interval for the true difference between the population proportions is [ - 0.0908, - 0.0092]

Learn more about confidence interval here:brainly.com/question/17421912

#SPJ4

7 0

1 year ago