<span>"C. Strategies facilitate objectives" This is true because there's a series of objectives that must be completed within any strategy, and the other options can be true however not for every strategy.</span>
<span>Virus protection software must be updated continually with information
on recently discovered viruses. A virus is a small, potentially damaging
computer program that can infect a computer without its user's knowledge.</span> Hackers often exploit well-known security vulnerabilities in popular
software to spread destructive programs such as viruses.
Answer:
PREPARING FOR THE TEST. The key to confidence in anything is preparation, and tests are no different. ...
KNOW HOW YOU LEARN. ...
MAKE A PLAN. ...
FIND A BUDDY. ...
REVIEW MATERIAL. ...
REST & EAT. ...
HANDLING ANXIETY. ...
TAKING THE TEST.
Explanation:
Answer:
A deductible
Explanation:
In insurance a deductible is the amount that a victim of an accident will have to.paynoit of his own pocket before the insurance pays for the rest.
When setting up an insurance the customer is allowed to set his deductible.
Lower deductibles attracts higher premium payments, while higher deductibles have lower premium payments.
In the scenario where Manny was in an accident with a bill totaling $11,500 and the insurance company says he needs to pay the first $1000. The $1,000 is the deductible amount
Answer:
![A = 28000 [\frac{0.12 (1.12)^4}{(1.12)^4 -1}]](https://tex.z-dn.net/?f=%20A%20%3D%2028000%20%5B%5Cfrac%7B0.12%20%281.12%29%5E4%7D%7B%281.12%29%5E4%20-1%7D%5D)
![A = 28000 [\frac{0.12*1.574}{1.574-1}]](https://tex.z-dn.net/?f=%20A%20%3D%2028000%20%5B%5Cfrac%7B0.12%2A1.574%7D%7B1.574-1%7D%5D)

So then the annual pay would be $ 9218.564 for this case
Explanation:
For this question we can use the Equivalent annual value (A) given by the following expression:
![A = PV [\frac{i (1+i)^t}{(1+i)^t -1}]](https://tex.z-dn.net/?f=%20A%20%3D%20PV%20%5B%5Cfrac%7Bi%20%281%2Bi%29%5Et%7D%7B%281%2Bi%29%5Et%20-1%7D%5D)
Where
represent the pesent value
since the rate is yearly
since we have 4 years to pay
So then we have everything to replace and we got:
![A = 28000 [\frac{0.12 (1.12)^4}{(1.12)^4 -1}]](https://tex.z-dn.net/?f=%20A%20%3D%2028000%20%5B%5Cfrac%7B0.12%20%281.12%29%5E4%7D%7B%281.12%29%5E4%20-1%7D%5D)
![A = 28000 [\frac{0.12*1.574}{1.574-1}]](https://tex.z-dn.net/?f=%20A%20%3D%2028000%20%5B%5Cfrac%7B0.12%2A1.574%7D%7B1.574-1%7D%5D)

So then the annual pay would be $ 9218.564 for this case
And this amount would be paid each year in order to pay all the money after 4 years.