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zubka84 [21]
4 years ago
7

GUEST

Mathematics
1 answer:
Vlad [161]4 years ago
5 0

Answer: 6 and 4

Step-by-step explanation:

Fill in the numbers with the correct variable and you get your answer. 6-0=6 6-2=4

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2X+15= -3x how do you work this equation​
Sphinxa [80]

Answer: x=-3

<u>Add 3x to both sides</u>

<u></u>2x+15+3x=-3x+3x\\5x+15=0<u></u>

<u></u>

<u>Subtract 15 from both sides</u>

<u></u>5x+15-15=0-15\\5x=-15<u></u>

<u></u>

<u>Divide both sides by 5</u>

<u></u>5x/5=-15/5\\x=-3<u></u>

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Answer:

\boxed{\text{A. }\math{\left \{ x \, | \, x \in \mathbb{R}, x < -2 \right \}}}}

Step-by-step explanation:

The open circle means that the point is not included in the solution set, and the arrow pointing left means that all numbers less than -2 are members.

In set-builder notation, each term has a special meaning. The braces enclose the members of the set.

Here's how you translate the notation,

\begin{array}{rcl}\\\left \{ & = & \text{The set of}\\x & = & \text{all x values}\\| & = &\text{such that}\\x & = & x\\\in & = &\text{is a member of}\\\mathbb{R}, & = &\text{all real numbers, and}\\x < -2 & = & \text{x is less than -2}\\\end{array}\\\text{The answer is }\boxed{\textbf{A. }\mathbf{\left \{ x \, | \, x \in \mathbb{R}, x < -2 \right \} }}}

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