D. Is the answer because its the only one that makes sense.
Should be 5,100 from the information that is given.
Answer:
The anchor should be located at the midpoint between the 20m high and 60m high antennas.
Step-by-step explanation:
Let the length of cable for 20m high antenna be represented by x, and that for 60m high antenna be y.
The single length of cable required = x + y.
From the principle of geometry, if the cable is anchored at 200m from the 20m high antenna, it forms a right angled triangle. Applying the Pythagoras theorem,
x =
= 199
Applying the same principle to the 60m high antenna gives,
y =
= 191
The single length of cable required = 199+ 191
= 390m
Varying the point of location of the anchor between the two antennas causes an increase in the length of cable required.
The anchor should be located at the midpoint between the two antennas to achieve a minimum amount of cable.
Answer:
f(2)=0
f(-4)=24
Step-by-step explanation:
We are given
f(n)=n^2-2n
We are asked which of the following are true?
f(2)=0
f(1)=3
f(-4)=24
f(5)=35
f(-2)=0
Let's start with f(2)=0.
f(2)=2^2-2(2)
f(2)=4-4
f(2)=0
So f(2)=0 is true.
Moving on to f(1)=3.
f(1)=1^2-2(1)
f(1)=1-2
f(1)=-1
So f(1)=3 is false.
Now for f(-4)=24.
f(-4)=(-4)^2-2(-4)
f(-4)=16+8
f(-4)=24
So f(-4)=24 is true.
f(5)=35?
f(5)=5^2-2(5)
f(5)=25-10
f(5)=15
So f(5)=35 is false.
Finally f(-2)=0.
f(-2)=(-2)^2-2(-2)
f(-2)=4+4
f(-2)=8
So f(-2)=0 is false.