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3 years ago

Yo I getting someones IG is easier than I thought l m a o

Mathematics

2 answers:

creativ13 [48]3 years ago

5 0

Y e s IDOKAPDNSIDBSKXNAXOANOXSNSOWNDOSMS

Alex17521 [72]3 years ago

5 0

Fs fs fs fs fs fs fs fs fs fs fs fs fs fs

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Easy, need help, thanks.

TEA [102]

Answer:

Step-by-step explanation:

The triangles are congruent bu HL.

m<RCD = m<PCD = 35 deg

5 0

3 years ago

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What conversion factor would you use to solve the problem 37in=_ft

Yakvenalex [24]

1 foot = 12 inches

Conversion factor is 12

7 0

3 years ago

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Use the diagram to find the measurement of the given angle

Over [174]

Answer:

Step-by-step explanation:

FAC = FAE + EAD +CAD

We know FAC = 180 and CAD = 50 and EAD = 90

180 = FAE + 90 +50

Combine like terms

180 = FAE + 140

Subtract 140 from each side

180-140 = FAE +140-140

40 = FAE

6 0

3 years ago

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Find k so that the distance from (–1, 1) to (2, k) is 5 units. k= k= *there are two solutions for 2*

dalvyx [7]

Answer:

k = -3

k =5

Step-by-step explanation:

$d = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}\\d = 5\\(-1,1) =(x_1,y_1)\\(2,k)=(x_2,y_2)\\$

$5=\sqrt{\left(2-\left(-1\right)\right)^2+\left(k-1\right)^2}\\\\\mathrm{Square\:both\:sides}:\quad 25=k^2-2k+10\\25=k^2-2k+10\\\\\mathrm{Solve\:}\:25=k^2-2k+10:\\k^2-2k+10=25\\\\\mathrm{Subtract\:}25\mathrm{\:from\:both\:sides}\\k^2-2k+10-25=25-25\\k^2-2k-15=0\\\\\mathrm{Solve\:by\:factoring}\\\\\mathrm{Factor\:}k^2-2k-15:\quad \left(k+3\right)\left(k-5\right)\\\mathrm{Solve\:}\:k+3=0:\quad k=-3\\$

$\mathrm{Solve\:}\:k-5=0:\quad k=5\\\\k =5 , k=-3$

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3 years ago

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Find x! I have no idea what it is

mash [69]

102+28=130 180-130=50, answer is 50°

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2 years ago

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