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3 years ago

Yo I getting someones IG is easier than I thought l m a o

Mathematics

2 answers:

creativ13 [48]3 years ago

5 0

Y e s IDOKAPDNSIDBSKXNAXOANOXSNSOWNDOSMS

Alex17521 [72]3 years ago

5 0

Fs fs fs fs fs fs fs fs fs fs fs fs fs fs

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Write an equation that is parallel to 3x-2y=14 and passes through point (-6,-11)

Allisa [31]

y = ( $\frac{3}{2}$ )x -2 is the equation of the required line

Step-by-step explanation:

Step 1 :

Equation of the given line is 3x-2y=14

Re writing this in the form y = mx + c , we have

-2y = -3x +14

y = ( $\frac{3}{2}$ )x - 7

The co efficient of x , m is the slope of the line. So for the given line the slope is $\frac{3}{2}$

Step 2 :

We have to find equation of a line which is parallel to this line. All parallel lines will have the same slope. Hence the required line has a slope of $\frac{3}{2}$ .

Step 3 :

Equation of line with slope m and passing through a point ( $x_{1} ,y_{1}$ ) is

(y- $y_{1}$ ) = m((x- $x_{1}$ )

So equation of line passing through (-6,-11) and with a slope of $\frac{3}{2}$ is

(y-(-11)) = $\frac{3}{2}$ ( x - (-6))

y + 11 = $\frac{3}{2}$ ( x + 6)

y = ( $\frac{3}{2}$ )x + 9 - 11

y = ( $\frac{3}{2}$ )x -2

Step 4 :

Answer :

y = ( $\frac{3}{2}$ )x -2 is the required equation

5 0

3 years ago

Can anyone help me solve a trigonomic identity problem and also help me how to do it step by step?

dusya [7]

$\bf cot(\theta)=\cfrac{cos(\theta)}{sin(\theta)}
\qquad csc(\theta)=\cfrac{1}{sin(\theta)}
\\\\\\
sin^2(\theta)+cos^2(\theta)=1\\\\
-------------------------------\\\\$

$\bf \cfrac{cos(\theta )cot(\theta )}{1-sin(\theta )}-1=csc(\theta )\\\\
-------------------------------\\\\
\cfrac{cos(\theta )\cdot \frac{cos(\theta )}{sin(\theta )}}{1-sin(\theta )}-1\implies \cfrac{\frac{cos^2(\theta )}{sin(\theta )}}{\frac{1-sin(\theta )}{1}}-1\implies 
\cfrac{cos^2(\theta )}{sin(\theta )}\cdot \cfrac{1}{1-sin(\theta )}-1
\\\\\\
\cfrac{cos^2(\theta )}{sin(\theta )[1-sin(\theta )]}-1\implies 
\cfrac{cos^2(\theta )-1[sin(\theta )[1-sin(\theta )]]}{sin(\theta )[1-sin(\theta )]}$

$\bf \cfrac{cos^2(\theta )-1[sin(\theta )-sin^2(\theta )]}{sin(\theta )[1-sin(\theta )]}\implies \cfrac{cos^2(\theta )-sin(\theta )+sin^2(\theta )}{sin(\theta )[1-sin(\theta )]}
\\\\\\
\cfrac{cos^2(\theta )+sin^2(\theta )-sin(\theta )}{sin(\theta )[1-sin(\theta )]}\implies \cfrac{\underline{1-sin(\theta )}}{sin(\theta )\underline{[1-sin(\theta )]}}
\\\\\\
\cfrac{1}{sin(\theta )}\implies csc(\theta )$

7 0

3 years ago

Luna is selling balloon animals at the park. She began with 35 balloons, and she has sold

Aleksandr [31]

Answer:

$12.25

i hope this helps

Step-by-step explanation:

5+2=7

1.75×7=12.25

7 0

4 years ago

What's (5X^10)/(15X^4X^6)

Vanyuwa [196]

Go on photomath and than scan the question and it’ll show you the work and everything

4 0

3 years ago

Read 2 more answers

The equation of line XY is (y−3) = negative 2 over 3(x − 4). What is the slope of a line perpendicular to XY?

artcher [175]

The answer would end up being -2/3

7 0

4 years ago