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Vikki [24]
3 years ago
9

Loge (k? + 2k)= log, 60 – loge 4

Mathematics
1 answer:
Nonamiya [84]3 years ago
6 0
Log(k + 2k) = log60 - log4
for two functions to be equal, the arguments of each must be equal
k = 5
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2x+5d-9×2c+844+233+2×+78d​
goldfiish [28.3K]

Answer:

−18c+83d+4x+1077

Step-by-step explanation:

combine all like terms

(2x+2x=4x)

(5d+78d=83d)

(-9*2c=-18c)

(1077=844+233)

5 0
3 years ago
Sort each equation according to whether it has one solution, infinitely many solutions, or no solution.
Aliun [14]
《ANSWER》

《LINEAR EQUATIONS》

Solving all we get as

↪1) 5 (x -2) = 5x - 7

since after solving X is cancelled , NO SOLUTION

↪2) -3 (x - 4) = -3x + 12

SINCE after solving X is any value , infinitely many solutions

↪3) 4 (x + 1) = 3x + 4

solving we get as , 4x+ 4 = 3x + 4 =》 X =0

only one solution

↪4) -2 (x-3) = 2x - 6

Only one solution

↪5) 6 (x + 5) = 6x + 11

NO SOLUTION

All the equations are solved by the distributive law of algebra
5 0
3 years ago
Read 2 more answers
I need help please help me
Elan Coil [88]
Here’s the correct answer and how I got it :)

6 0
3 years ago
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Which system of equations can you use to find the roots of the equation? x3 – 10x = x2 – 6 y = x3 – x2 + 10x + 6 y = 0 y = x3 –
Maslowich

Answer:

answer is:

y=x^{3}-10 x,y=x^{2}-6

Step-by-step explanation:

we are asked to find which system of equations can we use to find the roots of the equation:

x^{3}-10x=x^{2}-6

since the system of equation in last part is given as:

y=x^{3}-10 x,y=x^{2}-6

so, on equating both the equations i.e. on equating both the values of 'y' we get the desired equation as:

x^{3}-10x=x^{2}-6.


3 0
3 years ago
Read 2 more answers
Rewrite the following sentence as an equation.
SVEN [57.7K]

Answer:

3(2+x)=0

Step-by-step explanation:

<u>Here are some vocab words:</u>

Product: Multiplication

Sum: Addition

"A number": x

3(2+x)=0

6 0
3 years ago
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