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Free_Kalibri [48]
2 years ago
9

What is the area of the parallelogram represented by the vertices A(-6, -1), B(-2, -1), C(-1, -4) and D(-5, -4)?

Mathematics
1 answer:
kramer2 years ago
3 0

Answer: 12 units²

Step-by-step explanation:

To find the area of a parallelogram, we use the formula A=l×w. To find the length and width, let's graph out the parallelogram to get a better view. Let's refer to the picture attached to see what the graph looks like. The length is 4 units while the width is 3 units. Therefore we multiply.

A=4×3=12 units²

Now, we know the area is 12 units².

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Minor arc KL measures 135°. Circle O is shown. Line segments K O and O L are radii. Which is the radian measure of central angle
snow_lady [41]

StartFraction 3 pi Over 4 EndFraction radians

Step-by-step explanation:

Pi radians is equal to 180°

Given the minor arc angles as 135°, change this value to pi radians

180° =π radians

135° = ?

Cross multiply

135° * π radians / 180°

=135/180 *  π radians

=3 π/4  radians

Learn More

Changing degrees to radians :brainly.com/question/12095161

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#LearnwithBrainly

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Solve the equation on the interval [0,2π). cos^4x=cos^4xcscx
Alisiya [41]
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cos^4(x)[sin(x)-1]=0\to 
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\bf \measuredangle x = cos^{-1}(0)\implies \measuredangle x = 
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Eddi Din [679]

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hope it helps

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3 years ago
Julio bought a backpack for $39.95 and 2 belts for $17.99 each. The sales tax is 6%. How much did Julio spend for all the items,
gtnhenbr [62]

Answer:

$80.49

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