What is the area of the parallelogram represented by the vertices A(-6, -1), B(-2, -1), C(-1, -4) and D(-5, -4)?
1 answer:
Answer: 12 units²
Step-by-step explanation:
To find the area of a parallelogram, we use the formula A=l×w. To find the length and width, let's graph out the parallelogram to get a better view. Let's refer to the picture attached to see what the graph looks like. The length is 4 units while the width is 3 units. Therefore we multiply.
A=4×3=12 units²
Now, we know the area is 12 units².
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Here is your answer
Given area is
z^2 + 18z + 81
= z^2 + 2× z × 9 + 9^2
[using (a+b)^2= a^2 + 2ab + b^2], we get
= (z+9)^2
we know that area of a square is represented by side^2.
So, here
Side of square is
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