Answer:
The distance cover by him walking back is 11.25 miles
Step-by-step explanation:
Given as :
Time for Janelle to spend on training = 5 hours
The running speed of Janelle = 9 mph
The walking back with 3 mph
Let The distance for running and walking is same i.e D miles
SO, Time = 
∴ 5 = 
+ 
Or, 5 × 9 = D + 3 D
Or, 45 = 4 D
∴ D = 
= 11.25 miles
Hence The distance cover by him walking back is 11.25 miles Answer
The slope (“m” in the equation y = mx + b) in this equation is -2 but the slope of the line in which the coins follow is a positive slope meaning that that linear equation cannot capture the coins.
So first let’s make them improper. that will then make the equation 10/3 divided by 5/2 then you want to flip one so you can divide... that would be 3/10 divided by 5/2 and then you multiply across and get 10/6
Answer: t= 460.52 minutes
Step-by-step explanation:Q'=Q/100
Q'= rate in and out of water
Finding the differential equation
Let Q'(t)= The quantity of dye in the tank for t time
But rate in=0 Q/200 ×2=Q'
Q'/Q=-1/100
Dividing by Q gives
Ln/Q/ + c = -1/100 + c1
Integrating both sides gives
Ln/Q/ = -(1/100)t + c2
But c+c1=C2= A constant
Q=C2e(-t/100)
200e-(t/100)
t= ln200
t=460.52minutes
Answer: the answer is c
Step-by-step explanation:
