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Elza [17]
3 years ago
9

petra has 15 yards of fabric to make costumes for a paly. if each costume reqires 1,1/3 yards how many costumes can she make

Mathematics
1 answer:
RUDIKE [14]3 years ago
3 0

She can make 11 costumes

I found this by dividing the two numbers and when dividing them i got 11,1/4 but you can't have 1/4 of a costume so it would only be 11

Hope this helps

If there are any questions leave a comment

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45,133 lies between what and what
lana66690 [7]
Can  you explain more please
6 0
3 years ago
Openstudt what are the coordinates of the turning point for the function f(x) = (x − 2)3 + 1? (−2, −1) (−2, 1) (2, −1) (2, 1)
Dominik [7]

f(x) = (x - 2)^3 + 1

Find the derivative:-

f'(x) =   3(x -2)^2   This = 0 at the turning points:-

so 3(x - 2)^2 =  

giving x = 2 .  When x = 2     f(x)  =  3(2-2)^3 + 1 = 1

Answer is (2, 1)


3 0
2 years ago
You roll a pair of fair dice until you roll “doubles” (i.e., both dice are the same). what is the expected number, e[n], of roll
bonufazy [111]

We need to define our outcomes and events.

 

Finding the probability<span> of each event occurring separately, and then multiplying the probabilities is the step to <span>finding  the probability</span> of two independent events that occur in sequence.

</span>

<span>
To solve this problem, we take note of this:</span>

 

The roll of the two dice are denoted by the pair

(I, j) ∈ S={ (1, 1),(1, 2),..., (6,6) }

Each pair is an outcome. There are 36 pairs and each has probability 1/36. The event “doubles” is { (1, 1),(2, 2)(6, 6) } has probability p= 6/36 = 1/6. If we define ”doubles” as a successful roll, the number of rolls N until we observe doubles is a geometric (p) random variable and has expected value E[N] = 1/p = 6.

3 0
3 years ago
Suppose the round-trip airfare between Philadelphia and Los Angeles a month before the departure date follows the normal probabi
QveST [7]

Answer:

52.74% probability that a randomly selected airfare between these two cities will be between $325 and $425

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this question, we have that:

\mu = 387.20, \sigma = 68.50

What is the probability that a randomly selected airfare between these two cities will be between $325 and $425?

This is the pvalue of Z when X = 425 subtracted by the pvalue of Z when X = 325. So

X = 425

Z = \frac{X - \mu}{\sigma}

Z = \frac{425 - 387.20}{68.50}

Z = 0.55

Z = 0.55 has a pvalue of 0.7088

X = 325

Z = \frac{X - \mu}{\sigma}

Z = \frac{325 - 387.20}{68.50}

Z = -0.91

Z = -0.91 has a pvalue of 0.1814

0.7088 - 0.1814 = 0.5274

52.74% probability that a randomly selected airfare between these two cities will be between $325 and $425

7 0
2 years ago
Four friends go to an amusement arcade.
galben [10]

<u><em>Answer:</em></u>

<u>The rule is: </u>

T(x) = 8x + 20

<em><u>Explanation:</u></em>

<u>We are given that:</u>

<u>The rule for the amount that one friend pays is:</u>

C(x) = 2x + 5

<u>Now, we know that:</u>

Each of the four friends will pay the entry fee which is $5 per person

The 4 friends will play the same number of games represented by x

<u>This means that:</u>

We can simply get the rule for the total amount to be paid by the four friends (T(x)) by multiplying the amount paid by each friend by 4

<u>This means that:</u>

T(x) = 4 * C(x)

T(x) = 4(2x + 5)

T(x) = 8x + 20

Hope this helps :)

4 0
3 years ago
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