Answer:
2x^3 - 2x^2 - 3x -6 -(4/x^4 - 4x^3 + x^2 +2)
Step-by-step explanation:
x-2 = 0
since there is a missing x you have to put in a 0
2 | 1 -4 1 0 2
1 2 -4 -6 -6
1 -2 -3 -6 -4
x^3 x^2 x # remainder
bring down the 1 then multiply by 2 then add to -4
take the -2 multiply by 2 and add to 1 continuously do the samething
now take all the x's and go down one since you're taking out a x
put ing standard form
2x^3 - 2x^2 - 3x -6 -(4/x^4 - 4x^3 + x^2 +2)
i beleive that's the answer, good luck on whatever you're doing
