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3 years ago

9

12x-y,3/2n+1/2p,y²-1

1 answer:

vladimir2022 [97]3 years ago

7 0

What is this. what am i supposed to do here? solve it? idk what n,p,x, or y is.

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i f N(-7,-1) is a point on the terminal side of ∅ in standard form, find the exact values of the trigonometric functions of ∅.

Natali [406]

Answer:

$sin\ \varnothing = \frac{-1}{10}\sqrt 2$

$cos\ \varnothing = \frac{-7}{10}\sqrt 2$

$tan\ \varnothing = \frac{1}{7}$

$cot\ \varnothing = 7$

$sec\ \varnothing = \frac{-5}{7}\sqrt 2$

$csc\ \varnothing = -5\sqrt 2$

Step-by-step explanation:

Given

$N = (-7,-1)$ --- terminal side of $\varnothing$

Required

Determine the values of trigonometric functions of $\varnothing$ .

For $\varnothing$ , the trigonometry ratios are:

$sin\ \varnothing = \frac{y}{r}$ $cos\ \varnothing = \frac{x}{r}$ $tan\ \varnothing = \frac{y}{x}$

$cot\ \varnothing = \frac{x}{y}$ $sec\ \varnothing = \frac{r}{x}$ $csc\ \varnothing = \frac{r}{y}$

Where:

$r^2 = x^2 + y^2$

$r = \sqrt{x^2 + y^2$

In $N = (-7,-1)$

$x = -7$ and $y = -1$

So:

$r = \sqrt{(-7)^2 + (-1)^2$

$r = \sqrt{50$

$r = \sqrt{25 * 2$

$r = \sqrt{25} * \sqrt 2$

$r = 5 * \sqrt 2$

$r = 5 \sqrt 2$

<u>Solving the trigonometry functions</u>

$sin\ \varnothing = \frac{y}{r}$

$sin\ \varnothing = \frac{-1}{5\sqrt 2}$

Rationalize:

$sin\ \varnothing = \frac{-1}{5\sqrt 2} * \frac{\sqrt 2}{\sqrt 2}$

$sin\ \varnothing = \frac{-\sqrt 2}{5*2}$

$sin\ \varnothing = \frac{-\sqrt 2}{10}$

$sin\ \varnothing = \frac{-1}{10}\sqrt 2$

$cos\ \varnothing = \frac{x}{r}$

$cos\ \varnothing = \frac{-7}{5\sqrt 2}$

Rationalize

$cos\ \varnothing = \frac{-7}{5\sqrt 2} * \frac{\sqrt 2}{\sqrt 2}$

$cos\ \varnothing = \frac{-7*\sqrt 2}{5*2}$

$cos\ \varnothing = \frac{-7\sqrt 2}{10}$

$cos\ \varnothing = \frac{-7}{10}\sqrt 2$

$tan\ \varnothing = \frac{y}{x}$

$tan\ \varnothing = \frac{-1}{-7}$

$tan\ \varnothing = \frac{1}{7}$

$cot\ \varnothing = \frac{x}{y}$

$cot\ \varnothing = \frac{-7}{-1}$

$cot\ \varnothing = 7$

$sec\ \varnothing = \frac{r}{x}$

$sec\ \varnothing = \frac{5\sqrt 2}{-7}$

$sec\ \varnothing = \frac{-5}{7}\sqrt 2$

$csc\ \varnothing = \frac{r}{y}$

$csc\ \varnothing = \frac{5\sqrt 2}{-1}$

$csc\ \varnothing = -5\sqrt 2$

3 0

3 years ago

PLEASE HELP and can you show your work and say which number you are answering thank you

Svet_ta [14]

For # 9, the answer is 4 pants and 11 shirts, see in the comments for my explanation

4 0

3 years ago

Can somone pls help me with this I have a C- in math and I really need help also a like show work on each one plsss

Lady bird [3.3K]

Answer:

1. $\frac{3}{8}$

2. $\frac{1}{4}$

3a. $-\frac{1}{4}$

3b. 3

3c. $-\frac{4}{5}$

4. $m = \frac{y_1 - y_2}{x_1-x_2}\\$

Step-by-step explanation:

1.

Rises 6 inches for every horizontal change of 16 inches

Slope = rise/run

Slope = 6/16

Slope = 3/8

2.

Rises 3 feet for every horizontal change of 12 feet

Slope = rise/run

Slope = 3/12

Slope = 1/4

3a.

$m = \frac{y_1 - y_2}{x_1-x_2}$

$m = \frac{3-2}{-2-2}$

$m = \frac{1}{-4}$

$m = -\frac{1}{4}$

3b.

$m = \frac{y_1 - y_2}{x_1-x_2}\\$

$m = \frac{-1 - 2}{-1-0}$

$m = \frac{-3}{-1}$

$m = 3$

3c.

$m = \frac{y_1 - y_2}{x_1-x_2}\\$

$m = \frac{1 - (-3)}{-1-4}\\$

$m = \frac{4}{-5}\\$

$m = -\frac{4}{5}$

4.

$m = \frac{y_1 - y_2}{x_1-x_2}\\$

7 0

3 years ago

Subtract.<br> 15 - (-4)=

Sloan [31]

Answer: 19

Step by step:
15-(-4)
Negative* negative= positive
So.. negative 1 times -4=4
15+4= 19

5 0

3 years ago

Read 2 more answers

kayla thought of a number, added 4, multiplied by 3, subtracted 5, and got 28 as her final result. what number did she start wit

boyakko [2]

Answer:

21

Step-by-step explanation

5 0

3 years ago

Read 2 more answers