9514 1404 393
Answer:
- figure the areas of the rectangle and semicircle
- add them together
Step-by-step explanation:
The area of the rectangle is given by ...
A = LW
A = (20 m)(14 m) = 280 m²
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The area of the semicircle is ...
A = (1/2)πr²
A = (1/2)π(7 m)² = 24.5π m² ≈ 77 m²
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Then the total area is ...
280 m² +77 m² = 357 m²
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The width of the rectangle is the diameter of the circle, which is twice its radius. The area of a semicircle is 1/2 the area of a circle.
Part A:
I have attached the graph of this system of inequalities.
Part B:
Plug in (8,10) into both equations
10 > 3(8) + 10
10 > 24 + 10
10 > 34
This is false!
10 < (-3/4)(8) - 1
10 < (-3)(2) - 1
10 < -6 - 1
10 < -7
This is also false!
So,
(8,10) is not included in the solution area for the system.
You need to multiply the volume of a cone by 3 to get the volume of its corresponding cylinder (a cylinder with the same base radius and perpendicular height).
As in:
Vol. of a cylinder= πr²h
and Vol. of a cone= ⅓πr²h
So assuming volume of a cone is ⅓V, then the volume of the cylinder will be ⅓V × 3 which equals V.