What is the interquartile range for the set of data: 10, 3, 7, 6, 9, 12, 13
2 answers:
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Answer:
The area of quadrilateral ABCD is 139 unit^2.
Step-by-step explanation:
Given:
Quadrilateral ABCD whose vertices are A(1,1) B(7,-3) C(12,2) D(7,21).
Now, to find the area.
The coordinates of the quadrilateral are A(1,1), B(7,-3), C(12,2), D(7,21).
So, to find the area we need to bisect the quadrilateral ABCD and get the triangles ABC and ADC and then calculate their areas:
In Δ ABC:
Now, to get the area of triangle ABC:
On solving we get:
In Δ ADC:
Now, to get the area of triangle ADC:
On solving it by same process as above we get:
Now, to get the area of the quadrilateral we add the areas of the triangles ABC and ADC:
Therefore, area of quadrilateral ABCD is 139 unit^2.
Answer:
Two solutions
Step-by-step explanation:
This is a quadratic equation in the form y = ax² + bx + c.
For quadratic equations, you can find solutions using the quadratic formula:
.
To find the number of solutions, <u>you only need what's inside the square root</u>. We call it the "<u>discriminant</u>" because lets us know the number of solutions without solving.
If b²- 4ac > 0, two solutions. (greater than)
If b²- 4ac < 0, no solutions. (less than)
If b²- 4ac = 0, one solution. (equal to)
y = ax² + bx + c
y = -3x² + x + 12
a = -3 b = 1 c = 12
<u>Substitute into the discriminant</u>
b²- 4ac
= 1² - 4(-3)(12)
= 1 - (-144)
= 145 > 0
b²- 4ac > 0 Discriminant greater than 0
Therefore, there are two solutions.