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Tom [10]
3 years ago
11

16 POINTS-Someone please help me on this please I need help ASAP

Mathematics
1 answer:
Novay_Z [31]3 years ago
5 0

Answer:

I) They all are similar because they have same angles as the enlargement shows

a = 3*3=9

b=15÷20*12 would give you your answer

c = 4*3=12

Step-by-step explanation:

Hope this helps

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Hello!

You put -2 in for x

I don't know whether it is times x or to the power of x so I will do both

5 * 3 * x

5 * 3 * -2 = -30
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Hope this helps!
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A rectangle has its vertices at (-4, -3), (-4,7), (1,7), (1, -3). What part, in percent, of the rectangle is located in Quadrant
Rasek [7]

Consider the attached figure. The whole rectangle is ABCD, while AEGF is the part located in the third quadrant. In fact, this quadrant is composed by all the points with both coordinates negative.

To answer the question, let's compute the area of the two rectangles and see what part of ABCD is AEGF.

A and B have the same x coordinate, so the length of AB is given by the absolute difference of their y coordinates:

\overline{AB} = |A_y-B_y| = |-3-7| = |-10| = 10

Similarly, but exchanging the role of x and y, we compute the length of BC:

\overline{BC} = |B_x-C_x| = |-4-1| = |-5| = 5

So, the area of the rectangle is \overline{AB} \cdot \overline{BC} = 10\cdot 5 = 50

The same procedure allows us to compute width and height of the sub-rectangle in the third quadrant:

\overline{AE} = |A_y-E_y| = |-3-0| = |-3| = 3

\overline{EG} = |E_x-G_x| = |-4-0| = |-4| = 4

So, the area of the portion located in the third quadrant is \overline{AE} \cdot \overline{EG} = 3\cdot 4 = 12

This means that the ratio between the two area is

\cfrac{\text{area }AEGF}{\text{area }ABCD} = \cfrac{12}{50}

If we want this ratio to be a percentage, just make sure that the denominator is 100:

\cfrac{12}{50} = \cfrac{12}{50}\cdot \cfrac{2}{2} = \cfrac{24}{100} = 24\%

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3 years ago
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almond37 [142]

if we zero out f(x), namely make y = 0, we can get the roots or x-intercepts for this quadratic equation

\bf 0 = (x+4)(x-2)\implies \begin{cases} 0=x+4\implies &-4=x\\ 0=x-2\implies &2=x \end{cases}

now, the equation is in x-terms, meaning is a vertically opening parabola, so the axis of symmetry will be x = something, a vertical line.

well, we have two x-intercepts, one at -4 and another at 2, and the vertex is right half-way between those guys

-4------------(-1)------------2

so the vertex is at x=-1, namely the axis of symmetry is x = -1.

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