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maksim [4K]
3 years ago
14

Please help me solve !!

Mathematics
2 answers:
Rama09 [41]3 years ago
6 0
The answer to this question is 5
Viefleur [7K]3 years ago
4 0

Answer:

there’s not enough information for me to help

Step-by-step explanation:

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Assume that the random variable X is normally​ distributed, with mean mu equals 100 and standard deviation sigma equals 20. Comp
TEA [102]

Answer: 0.2119

Step-by-step explanation:

We assume that the random variable X is normally​ distributed.

Given : Population mean : \mu=100

Standard deviation : \sigma=20

Z-score : z=\dfrac{x-\mu}{\sigma}

Then, z-score corresponds to 116

z=\dfrac{116-100}{20}=0.8

By using the standard normal distribution table for z , we have

P(x>116)=P(z>0.8)=1-P(z\leq0.8)

=1-0.7881446\approx0.2119

Hence, the required probability = 0.2119

4 0
4 years ago
Expand and simplify<br><br>3(x-y)+4(x+2y)​
melomori [17]

Answer:

3x-3y+4x+8y

The answer is: 7+5y

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
Solve for k<br>4k=10+2k​
Airida [17]
K=5

Explanation: you have to rearrange the terms to make the problem look easier to solve then you have you subtract 2 from both sides of the equation then once you get that you have to simplify your answer (combine like terms) then after you divide both sides by 2 and then you should get your answer which is 5 here is a picture of the steps if you don't get it Hope this helps!

8 0
3 years ago
Please help asap find f -1
ExtremeBDS [4]
I.
Given a function f with domain D and range R, and the inverse function 
f ^{-1},

then the domain of f ^{-1} is the range of f, and the range of f ^{-1} is the domain of f.

II. We are given the function f(x)= \sqrt{x-5},

the domain of f, is the set of all x for which \sqrt{x-5} makes sense, so x is any x for which x-5\geq0, that is x≥5.

the range is the set of all values that f can take. Since f is a radical function, it never produces negative values, in fact in can produce any value ≥0

Thus the Domain of f is [5, ∞) and the Range is [0, ∞)
then , the Domain of f ^{-1} is [0, ∞) and the Range of f ^{-1} is [5, ∞) 

III.
Consider f(x)= \sqrt{x-5}

to find the inverse function f^{-1}, 

1. write f(x) as y:

y= \sqrt{x-5}

2. write x in terms of y:

y= \sqrt{x-5}

take the square of both sides

y^{2} =x-5

add 5 to both sides

y^{2} +5=x

x=y^{2} +5

3. substitute y with x, and x with f^{-1}(x):

f^{-1}(x)=x^{2} +5


These steps can be applied any time we want to find the inverse function.

IV. Answer: 

f^{-1}(x)=x^{2} +5, x≥0

y≥0, where y are all the values that f^{-1} can take

Remark: the closest choice is B

8 0
3 years ago
PLEASE HELP ASSAAPPPPP
Marysya12 [62]
A. -h to the 20th power 
3 0
3 years ago
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