Question

If you answer these two questions, that would be awesome, on my other questions i have asked the same one twice so if you want more points go on to my other questions and just put the same thing. hopefully someone see's this.

Answer 1

Answer:

$\huge \boxed{\sqrt[3]{x^{2} } } \\ \\ \huge \boxed{x^{\frac{3}{4} } }$

Step-by-step explanation:

Part 1:

x^(5/6) ÷ x^(1/6)

Applying exponent rule : a^b ÷ a^c = a^(b-c)

x^(5/6-1/6)

x^(4/6)

Simplifying the exponent.

x^(2/3)

Converting to simplest radical form.

(x^2)^(1/3)

$\sqrt[3]{x^{2} }$

Part 2:

$\sqrt{x} \times \sqrt[4]{x}$

Converting to exponent form.

x^(1/2) × x^(1/4)

Applying exponent rule : a^b × a^c = a^(b+c)

x^(1/2+1/4)

x^(2/4+1/4)

x^(3/4)

Answer 2

Answer:

$\sqrt[3]{x^2}$

x ^( 1/8)

Step-by-step explanation:

x ^ (5/6)  ÷ x ^ (1/6)

We know that a^ b ÷ a ^c = a^ ( b-c)

x^ ( 5/6 - 1/6)

x^ (4/6)

x ^ 2/3

$\sqrt[3]{x^2}$

$\sqrt{x}$$\sqrt[\\4]{x}$

x ^ 1/2 * x ^ 1/4

We know that a^ b * a ^ c = a^ (b*c)

x ^ (1/2 * 1/4)

x ^( 1/8)