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PtichkaEL [24]
2 years ago
11

In a state lottery, you must correctly select 5 numbers (in any order) out of 40 to win the top prize. 1. How many ways can 5 nu

mbers be chosen from 40 numbers? 2. You purchase one lottery ticket. What is the probability that you will win the top prize? 3. If the order of the numbers mattered, will the probability of winning increase or decrease? Why?
Mathematics
2 answers:
Crazy boy [7]2 years ago
6 0

Answer:

In a state lottery, you must correctly select 5 numbers (in any order) out of 40 to win the top prize.

1. How many ways can 5 numbers be chosen from 40 numbers?

40C5 = \frac{40!}{5!\times35!} = 658008 ways.

2. You purchase one lottery ticket. What is the probability that you will win the top prize?

The answer is 5! ways or 120 ways.

Hence, probability of winning top prize =\frac{120}{658008} =0.0001 or 0.01 %

3. The order of the numbers mattered, will the probability of winning increase or decrease? Why?

The probability decreases.

The probability of winning a game when order matters is always less than the probability of winning a game when order does not matter. This is because the permutation is always greater than the combination.

Sergeeva-Olga [200]2 years ago
4 0

Answer:

If the number has 5 numbers in any order (different ones)

The number of possible combinations is equal to product of the number of options that we have for each of the 5 numbers.

For the first one we have 40 numbers to choice.

for the second one we have 39, because we already took one.

for the third one we have 38

for the fourth we have 37

for the fifth we have 36

Then the number of combinations is:

40*37*38*37*36 = 78960960

and because the order does not matter, we need to divide by the posible permutations, for a 5 digit number the number of permutations is:

5 options for the first digit.

4 for the second.

3 for the third.

and so on:

P = 5*4*3*2*1 = 5!

so the number of combinations is: c = 78960960/5! = 658008

This means that if you buy a ticket, your probability of winning is 1 out of 658008, or p =  1/658008.

And if the order actually does matter, we use the previous number, with only 1 ticket the probability is 1 out of 78960960 or p = 1/78960960 which is a lot smaller.

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2 years ago
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4 0
2 years ago
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I need help with geometry:
nikklg [1K]

Answer:

x = 5

Step-by-step explanation:

6/18 = x/(20-x)

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3 0
2 years ago
What is the distance between (2,-9) and (-1,4)
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Answer:

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7 0
2 years ago
Need help please help me
ANTONII [103]
Megan:
x to the one third power =  x ^{1/3}
<span>x to the one twelfth power = </span>x ^{1/12}

<span>The quantity of x to the one third power, over x to the one twelfth power is:
</span>\frac{x ^{1/3}}{x ^{1/12}}
<span>
Since </span>\frac{ x^{a} }{ x^{b} } = x ^{a-b}
then \frac{x ^{1/3}}{x ^{1/12}} = x^{1/3-1/12}

Now, just subtract exponents:
1/3 - 1/12 = 4/12 - 1/12 = 3/12 = 1/4

\frac{x ^{1/3}}{x ^{1/12}} = x^{1/3-1/12} = x^{1/4}


Julie:
x times x to the second times x to the fifth = x * x² * x⁵

<span>The thirty second root of the quantity of x times x to the second times x to the fifth is
</span>\sqrt[32]{x* x^{2} * x^{5} }
<span>
Since </span>x^{a}* x^{b}= x^{a+b}
Then \sqrt[32]{x* x^{2} * x^{5} }= \sqrt[32]{ x^{1+2+5} } =\sqrt[32]{ x^{8} }

Since \sqrt[n]{x^{m}} = x^{m/n} }
Then \sqrt[32]{ x^{8} }= x^{8/32} = x^{1/4}

Since both Megan and Julie got the same result, it can be concluded that their expressions are equivalent.
3 0
3 years ago
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