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borishaifa [10]
2 years ago
6

what is the answer of This The next day I got home from school and there was nothing baking in the oven nor any dishes in the si

nk. I went to my room and everything was back to “normal.” On my bed was a box with beautiful wrapping and a handmade bow. I opened the package, saving the bow. I hugged the gorgeous white angora sweater and whispered to the air, “Good-bye, Phyllis and Charlie, and thanks.”
Mathematics
1 answer:
Svetllana [295]2 years ago
7 0
Honestly i have no clue what ur talking abt
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Find the slope of line passing through the two points, (3, 6) and (3, 2)
lilavasa [31]

Answer:

It is undefined

Step-by-step explanation:

Slope formula:

m = y₂ - y₁ / x₂ - x₁

m = 2 - 6 / 3 - 3

m = -4 / 0

m = 0

From this calculation, there is no slope because the two points have the same x variable, which will result to a no run.

It would be a vertical line.

4 0
3 years ago
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Determine the area of the following circle
sleet_krkn [62]

Answer:

31.6 sq.in i got by using 2pier formula

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3 years ago
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Maria throws a softball straight up into the air with an initial velocity of 50 ft/sec. The ball leaves her hand when it is exac
Nataly_w [17]

Answer:

The equation that models the situation is s_{f} = 4+\frac{v_{f}^{2}-2500}{64.348}.

Step-by-step explanation:

Let suppose that effects from air friction and Earth's rotation can be neglected, so that the softball can be modelled experiment a free fall, that is, an uniform accelerated motion due to gravity. From we know the initial velocity and position of the position and we can determine the final position of the ball as a function of the final velocity:

v_{f}^{2} = v_{o}^{2}+2\cdot a \cdot (s_{f}-s_{o}) (1)

Where:

s_{o}, s_{f} - Initial and final position of the softball, measured in feet.

a - Acceleration, measured in meters per square second.

v_{o}, v_{f} - Initial and final velocities of the softball, measured in feet per second.

If we know that v_{o} = 50\,\frac{ft}{s}, a = -32.174\,\frac{m}{s^{2}} and s_{o} = 4\,ft, then the equation that models the situation is:

v_{f}^{2} = 2500-64.348\cdot (s_{f}-4)

Then, we clear the final position of the softball:

-\frac{v_{f}^{2}-2500}{-64.348} = s_{f}-4

s_{f} = 4+\frac{v_{f}^{2}-2500}{64.348}

The equation that models the situation is s_{f} = 4+\frac{v_{f}^{2}-2500}{64.348}.

8 0
2 years ago
Help please need it fast
shepuryov [24]
I think its $3.43 per pair of sock
3 0
3 years ago
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Find the midpoint of the line segment with the given endpoints (-4,4) (5,-1)
seraphim [82]

Answer:

(1/2), (3/2)

Step-by-step explanation:

midpoint fomula

(x1+x2)/ 2,  (y1+y2)/2

(5-4)= 1    1/2 = (1/2)

(-1+4)=3    3/2=(3/2)

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3 years ago
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