The expression that represents the product of negative three-fourths x and –8x is 6x^2
<h3>How to determine the equivalent expression?</h3>
The statement is given as:
the product of negative three-fourths x and –8x
Rewrite properly as:
-3x/4 * -8x
Divide 4 and 8 by 4
-3x * -2x
Multiply -3 and -2
6x * x
Multiply x and x
6x^2
Hence, the expression that represents the product of negative three-fourths x and –8x is 6x^2
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Answer:
A. y =
- 1
Step-by-step explanation:
Given parameters:
Equation of the line:
5x + 2y = 12
Coordinates = -2, 4
Unknown:
The equation of the line parallel to this line = ?
- To solve this problem, first, we need to find the slope of the given line.
Every linear equation have the formula: y = mx + c
m is the slope of the line, c is the y- intercept
5x + 2y = 12
Express this equation as y = mx + c
2y = -5x + 12
y =
+ 6
The slope of this line is 
- Now, any line that is parallel to another will not cut or cross it at any point. This simply implies they have the same slope.
Slope of the line parallel is 
- Our new line will also take the form y=mx + c,
Coordinates = -2, 4, x = -2 and y = 4
m is 
Now let us solve for C, the y-intercept;
4 = - 2 x
+ C
4 = 5 + C
C = -1
The equation of the line is therefore;
y =
- 1
15.12m2 just finished the test
Answer/Step-by-step explanation:
✔️Find EC using Cosine Rule:
EC² = DC² + DE² - 2*DC*DE*cos(D)
EC² = 27² + 14² - 2*27*14*cos(32)
EC² = 925 - 756*cos(32)
EC² = 283.875639
EC = √283.875639
EC = 16.85 cm
✔️Find the area of ∆DCE:
Area = ½*14*27*sin(32)
Area of ∆DCE = 100.15 cm²
✔️Since ∆DCE and ∆ABE are congruent, therefore,
Area of ∆ABE = 100.15 cm²
✔️Find the area of the sector:
Area of sector = 105/360*π*16.85²
Area = 260.16 cm² (nearest tenth)
✔️Therefore,
Area of the logo = 100.15 + 100.15 + 260.16 = 460.46 ≈ 460 cm² (to 2 S.F)
Answeri think it’s 96 or 84 I’m. It sure I had this like 3 years ago
Step-by-step explanation: