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3 years ago

HElP plS anD ty. ;-;....

Mathematics

1 answer:

Minchanka [31]3 years ago

8 0

Answer:

hi you might want to attach a file or copy and paste so people could help!

Step-by-step explanation:

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Pleeeeeeassesesesaerxvdrcgcdrcxf help me

Aleksandr-060686 [28]

Answer:

The solution is r <u>></u> 7.

Closed circle at 7 with an arrow pointing to the right

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

Simplify 3^2/3.3^1/5

san4es73 [151]

ANSWER:

$\frac{1}{5} \\$

EXPLANATION:

$\frac{ \frac{{3}^{2}}{3 \times{3}^{1}}}{5} = \\$

$\frac{ \frac{9}{3 \times 3} }{5} = \\$

$\frac{ \frac{9}{9} }{5} = \\$

$\frac{1}{5} \\$

4 0

3 years ago

Let's find2. 1+5 3First write the addition with a common denominator.Then add.12— +51-4-13Х5

emmasim [6.3K]

Answer: $\frac{2}{5}+\frac{1}{3}=\frac{6}{15}+\frac{5}{15}=\frac{11}{15}$ Explanation:

The given addition exercise is:

$\frac{2}{5}+\frac{1}{3}$

The LCM of the denominator (5 and 3) = 15

Multiply 2/5 by 3/3

$\frac{2}{5}=\frac{2\times3}{5\times3}=\frac{6}{15}$

Multiply 1/3 by 5/5

$\frac{1}{3}=\frac{1\times5}{3\times5}=\frac{5}{15}$

The addition becomes

$\frac{6}{15}+\frac{5}{15}=\frac{11}{15}$

Therefore, we can fill in the vacant boxes as shown below:

$\frac{2}{5}+\frac{1}{3}=\frac{6}{15}+\frac{5}{15}=\frac{11}{15}$

4 0

1 year ago

Which ordered pair (a,b) is a solution to the given system of linear equations.

egoroff_w [7]

Answer:

A. (-13,-3)

Step-by-step explanation:

Solve the system of two equations:

$\left\{\begin{array}{l}-2a+3b=14\\a-4b=3\end{array}\right.$

From the second equation:

$a=3+4b$

Substitute it into the first equation:

$-2(3+4b)+3b=14\\ \\-6-8b+3b=14\\ \\-8b+3b=14+6\\ \\-5b=20\\ \\5b=-20\\ \\b=-4$

So,

$a=3+4b=3+4\cdot (-4)=3-16=-13$

The solution is (-13,-4)

6 0

3 years ago

Read 2 more answers

Please help me with this math question will mark brainliest

LenaWriter [7]

Answer:

-9

Step-by-step explanation:

Using the sum/difference property of logarithms, we can rewrite the expression given as:

log b^3 + log c^3 - log √(a^3) --> log √(a^3) can also be written as log a^1.5

Next, we can use the power property of logarithms, and rewrite it again as:

3log b + 3log c - 1.5log a

Now, we can substitute the values of log a, log b, and log c:

3(11) + 3(-9) - 1.5(10)

33 - 27 - 15

-9

Simplifying, we get -9 as the answer.

3 0

3 years ago