All categories

3 years ago

In your own words what is the difference between an 'Equation' and 'Inequality' ?

Mathematics

1 answer:

goblinko [34]3 years ago

6 0

An equation is a math problem that must be solved to find out to find out a difference, quotient, sum, or product.

An inequality is a math problem that must be solved to find out what the difference is between two numbers.

You might be interested in

A 4000 kg truck is parked on a 7.0° slope. How big is the friction force on the truck?

Lelu [443]

Answer:

4777.28 N

Step-by-step explanation:

The gravitational force down the slope is given by the formula;

(mass *g * sin θ )

where;

θ is the angle of inclination of the slope

g is the gravitational pull

We plug in the given values into the above expression;

(4,000 x 9.8 x sin 7) = 4777.28 N.

The frictional force must equal to 4777.28 N (pointing up the slope).

5 0

3 years ago

Mark had 312 books. He has 11 times more fiction than nonfiction. How many fiction does he have

andrew11 [14]

He has about 28 fiction books. Since 312 divided by 11 is equal to 28.3636363636, you can't have a decimal number for the amount of books, so you round down to 28.

8 0

3 years ago

9 cm 7 cm 7 cm 9cm 9 cm

Mrac [35]

Answer:

Step-by-step explanation:

7 0

3 years ago

Find the quotient using long division 6x2 - 8x + 5/ X-2

joja [24]

Step-by-step explanation:

hope this helps have a great day!

3 0

3 years ago

Solving Rational Functions Hello I'm posting again because I really need help on this any help is appreciated!!

Greeley [361]

Answer:

x = √17 and x = -√17

Step-by-step explanation:

We have the equation:

$\frac{3}{x + 4} - \frac{1}{x + 3} = \frac{x + 9}{(x^2 + 7x + 12)}$

To solve this we need to remove the denominators.

Then we can first multiply both sides by (x + 4) to get:

$\frac{3*(x + 4)}{x + 4} - \frac{(x + 4)}{x + 3} = \frac{(x + 9)*(x + 4)}{(x^2 + 7x + 12)}$

$3 - \frac{(x + 4)}{x + 3} = \frac{(x + 9)*(x + 4)}{(x^2 + 7x + 12)}$

Now we can multiply both sides by (x + 3)

$3*(x + 3) - \frac{(x + 4)*(x+3)}{x + 3} = \frac{(x + 9)*(x + 4)*(x+3)}{(x^2 + 7x + 12)}$

$3*(x + 3) - (x + 4) = \frac{(x + 9)*(x + 4)*(x+3)}{(x^2 + 7x + 12)}$

$(2*x + 5) = \frac{(x + 9)*(x + 4)*(x+3)}{(x^2 + 7x + 12)}$

Now we can multiply both sides by (x^2 + 7*x + 12)

$(2*x + 5)*(x^2 + 7x + 12) = \frac{(x + 9)*(x + 4)*(x+3)}{(x^2 + 7x + 12)}*(x^2 + 7x + 12)$

$(2*x + 5)*(x^2 + 7x + 12) = (x + 9)*(x + 4)*(x+3)$

Now we need to solve this:

we will get

$2*x^3 + 19*x^2 + 59*x + 60 = (x^2 + 13*x + 3)*(x + 3)$

$2*x^3 + 19*x^2 + 59*x + 60 = x^3 + 16*x^2 + 42*x + 9$

Then we get:

$2*x^3 + 19*x^2 + 59*x + 60 - ( x^3 + 16*x^2 + 42*x + 9) = 0$

$x^3 + 3x^2 + 17*x + 51 = 0$

So now we only need to solve this.

We can see that the constant is 51.

Then one root will be a factor of 51.

The factors of -51 are:

-3 and -17

Let's try -3

p( -3) = (-3)^3 + 3*(-3)^2 + +17*(-3) + 51 = 0

Then x = -3 is one solution of the equation.

But if we look at the original equation, x = -3 will lead to a zero in one denominator, then this solution can be ignored.

This means that we can take a factor (x + 3) out, so we can rewrite our equation as:

$x^3 + 3x^2 + 17*x + 51 = (x + 3)*(x^2 + 17) = 0$

The other two solutions are when the other term is equal to zero.

Then the other two solutions are given by:

x = ±√17

And neither of these have problems in the denominators, so we can conclude that the solutions are:

x = √17 and x = -√17

6 0

3 years ago