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4 years ago

What is the volume of this rectangular prism? 2 cm 1 cm 1/4 cm

Mathematics

2 answers:

mixas84 [53]4 years ago

8 0

O.75 cm i think sorry if I’m wrong

Setler [38]4 years ago

3 0

Answer:

0.5

Step-by-step explanation:

L*W*H

1*1/4 or 0.25 *2=0.5 cm I think so

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What is the slope of the line between -7,-2 and 9,4?

Novay_Z [31]

the answer is 6/16. or if u simplify u will get the equivalent fraction or simplified fraction 3/8

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3 years ago

Can anyone help me!! You don’t have to answer all just one would be fine!

netineya [11]

Answer:

3. SinD= 12/15; Sin E= 9/15

4. sinD= 35/37; sinE= 12/37

5. sinD= 28/53; sinE= 45/53

6. Because the numerator should be 12 since that is the side opposite to the angle A.

Step-by-step explanation:

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4 years ago

PLZ help really super fast

BaLLatris [955]

Answer:

Step-by-step explanation:

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3 years ago

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Set up a triple integral in spherical coordinates to compute the volume of the region inside the sphere x² + y² + z² = 4 and abo

Mademuasel [1]

The plane meets the sphere in the cylinder

$z=1 \implies x^2+y^2+1^2 = 4 \implies x^2+y^2 = 3 = \left(\sqrt3\right)^2$

In spherical coordinates, the plane has equation

$z = \rho\cos(\phi) = 1 \implies \rho = \sec(\phi)$

and since

$\begin{cases}x = \rho\cos(\theta)\sin(\phi) \\ y=\rho\sin(\theta)\sin(\phi)\end{cases} \implies x^2+y^2 = \rho^2 \sin^2(\phi)$

the cylinder has equation

$\rho^2 \sin^2(\phi) = 3 \implies \rho = \sqrt3 \, \csc(\phi)$

The plane and cylinder thus meet when

$\sec(\phi) = \sqrt3\,\csc(\phi) \implies \tan(\phi) = \sqrt3 \implies \phi = \dfrac\pi3$

So, the volume of the region is given by

$\displaystyle \boxed{\int_0^{2\pi} \int_0^{\pi/3} \int_{\sec(\phi)}^2 \rho^2 \sin(\phi) \, d\rho \, d\phi \, d\theta}$

7 0

2 years ago

After 273 m3 of ethylene oxide is formed at 748 kPa and 525 K, the gas is cooled at constant volume to 293 K.The new pressure is

Anuta_ua [19.1K]

P1/T1 = P2/T2

<span>748 / 525 = P2/293 </span>

<span>P2 = 748/525 X 293 = 417.455 kPa </span>

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4 years ago

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