Answer:
18.6 months
Step-by-step explanation:
Given that :
Best fit line from scatterplot :
y=-12.05x +224.26
x = Number of month
y = charge on battery
Number of months a typical battery uses before being dead completely :
When battery is dead completely ; charge =0, y = 0
y = -12.05x + 224.26
0 = - 12.05x + 224.26
12.05x = 224.26
x = 224.26 / 12.05
x = 18.610788
Hence, 18.6 months before battery is completely dead.
I’m going with none because it would just be N-W= blank. Is the blank n or w. I mean it could be one of those but I don’t think you know enough about the question for it to be N or W. So I would say none. Sorry if I’m wrong.
Answer:
b(b/a)^2
Step-by-step explanation:
Given that the value of the car depreciates such that its value at the end of each year is p % less than its value at the end of the previous year and that car was worth a dollars on December 31, 2010 and was worth b dollars on December 31, 2011, then
b = a - (p% × a) = a(1-p%)
b/a = 1 - p%
p% = 1 - b/a = (a-b)/a
Let the worth of the car on December 31, 2012 be c
then
c = b - (b × p%) = b(1-p%)
Let the worth of the car on December 31, 2013 be d
then
d = c - (c × p%)
d = c(1-p%)
d = b(1-p%)(1-p%)
d = b(1-p%)^2
d = b(1- (a-b)/a)^2
d = b((a-a+b)/a)^2
d = b(b/a)^2 = b^3/a^2
The car's worth on December 31, 2013 = b(b/a)^2 = b^3/a^2
Answer: What question am I answering
Step-by-step explanation:
