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ladessa [460]
3 years ago
10

Tan(x - 3 π ) = _____ -1 1 -tanx tanx

Mathematics
1 answer:
vesna_86 [32]3 years ago
3 0

\bf \textit{Sum and Difference Identities} \\\\ tan(\alpha + \beta) = \cfrac{tan(\alpha)+ tan(\beta)}{1- tan(\alpha)tan(\beta)} \qquad tan(\alpha - \beta) = \cfrac{tan(\alpha)- tan(\beta)}{1+ tan(\alpha)tan(\beta)} \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ tan(x-3\pi )=\cfrac{tan(x)-tan(3\pi )}{1+tan(x)tan(3\pi )} \\\\[-0.35em] ~\dotfill

\bf tan(3\pi )\implies \cfrac{sin(3\pi )}{cos(3\pi )}\implies \cfrac{0}{-1}\implies 0\qquad therefore \\\\[-0.35em] ~\dotfill\\\\ tan(3\pi )=\cfrac{tan(x)-tan(3\pi )}{1+tan(x)tan(3\pi )}\implies tan(x-3\pi )=\cfrac{tan(x)-0}{1+0} \\\\\\ tan(x-3\pi )=\cfrac{tan(x)}{1}\implies tan(x-3\pi )=tan(x)

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Step-by-step explanation:

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8 0
4 years ago
A company that manufactures and sells consumer video cameras sells two versions of their popular hard disk​ camera, a basic came
saul85 [17]

Answer:

The percentage of customers who buy an extended warranty is 33%.

Step-by-step explanation:

In this problem, we have these following percentages.

35% of the customers select the basic camera.

This also means that:

65% of the customers select the deluxe version. (Since you can buy only two versions of the hard disk camera and the sum of the percentages is 100%).

20% of those who select the basic camera also purchase the extended warranty.

40% of those who select the deluxe version also purchase the extended warranty.

What is the percentage of customers who buy an extened warranty?

P = P_{1} + P_{2}

P_{1} is the percentage of those who buy the basic version with the extended warranty. So it is 20% of 35%. So

P_{1} = 0.20*0.35 = 0.07

P_{2} is the percentage of those who buy the deluxe version with the extended warranty. So it is 40% of 65%. So

P_{2} = 0.40*0.65 = 0.26

P = P_{1} + P_{2} = 0.07 + 0.26 = 0.33

The percentage of customers who buy an extended warranty is 33%.

3 0
4 years ago
What is the measure of the space occupied by a solid. (Measured in cubic units)
Studentka2010 [4]
Volume. Hope this helps!
7 0
3 years ago
Thomas invested $8,500 for one year. Part of the money was invested at6% and the rest at 9%. The total interest earned was $667.
oee [108]
Okay so say that x=amount invested with 6% and y=amount invested with 9%
x+y=8,500 so > x=8500-y
6%=0.06        <span>9%=0.09</span>
0.06x +0.09y=667.5 (Substitute in x=8500-y so only numbers and y)
0.06(8500-y)+0.09y=667.5 (expand brackets)
510-0.06y+0.09y=667.5 (-510)
0.03y=117.5 (/0.03)
$3916.67=Y  ->9%
X=8500-Y 
x=$4583.33 ->6%
4 0
4 years ago
9 hours = days can anyone tell me<br>​
stealth61 [152]

How many minutes are in 9 hrs

1 hr = 60 min

You must apply dimensional analysis (aka setting up fractions where the units you want will cancel out and the ones you want stay)

\frac{9 hr}{1} *\frac{60 min}{1hr}

9 hrs is 540 min

Hope this helped!

~Just a girl in love with Shawn Mendes

7 0
3 years ago
Read 2 more answers
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