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3 years ago

Tan(x - 3 π ) = _____ -1 1 -tanx tanx

1 answer:

3 0

$\bf \textit{Sum and Difference Identities} \\\\ tan(\alpha + \beta) = \cfrac{tan(\alpha)+ tan(\beta)}{1- tan(\alpha)tan(\beta)} \qquad tan(\alpha - \beta) = \cfrac{tan(\alpha)- tan(\beta)}{1+ tan(\alpha)tan(\beta)} \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ tan(x-3\pi )=\cfrac{tan(x)-tan(3\pi )}{1+tan(x)tan(3\pi )} \\\\[-0.35em] ~\dotfill$

$\bf tan(3\pi )\implies \cfrac{sin(3\pi )}{cos(3\pi )}\implies \cfrac{0}{-1}\implies 0\qquad therefore \\\\[-0.35em] ~\dotfill\\\\ tan(3\pi )=\cfrac{tan(x)-tan(3\pi )}{1+tan(x)tan(3\pi )}\implies tan(x-3\pi )=\cfrac{tan(x)-0}{1+0} \\\\\\ tan(x-3\pi )=\cfrac{tan(x)}{1}\implies tan(x-3\pi )=tan(x)$

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Please help me its a math problem thank you i give brainlist

inna [77]

Answer:

1.875

Step-by-step explanation:

the average rate of change of g(x) in the closed interval [ a, b ] is

$\frac{g(b)-g(a)}{b-a}$

here [a, b ] = [- 1, 3 ] , then

g(b) = g(3) = 2³ + 1 = 8 + 1 = 9

g(a) = g(- 1) = $2^{-1}$ + 1 = $\frac{1}{2}$ + 1 = 1.5

then

average rate of change = $\frac{9-1.5}{3-(-1)}$ = $\frac{7.5}{4}$ = 1.875

8 0

3 years ago

Read 2 more answers

Please help ASAP this is due very soon and I need help.

mihalych1998 [28]

Answer:

Step-by-step explanation:

just add all the sides

5+5+2+2= 14

8 0

3 years ago

Find the value for x in the rectangular prism. Use exact values.

Svetlanka [38]

Answer:

x = 2 $\sqrt{66}$

Step-by-step explanation:

x = $\sqrt{2^2+8^2+14^2}$

= $\sqrt{4+64+196}$

= $\sqrt{264}$

= 2 $\sqrt{66}$

8 0

3 years ago

The length of a rectangle is 3.5 inches more tan its width. The perimeter of the rectangle is 31 inches. Find the length and the

leonid [27]

Length (L): w + 3.5

width (w): w

Perimeter (P) = 2L + 2w

31 = 2(w + 3.5) + 2(w)

31 = 2w + 7 + 2w

31 = 4w + 7

24 = 4w

6 = w

Length (L): w + 3.5 = (6) + 3.5 = 9.5

Answer: width = 6 inches, length = 9.5 inches

8 0

3 years ago

What is the relationship between the conversion factors used in Part A of Model 2? Whatabout the conversion factors used in Part

Lelu [443]

Given:

The conversions from meter to inches and inches to meter are shown in part A of model 2.

The conversions from liters to quarts and quarts to liters are shown in part B of model 2.

Required:

To find the relationship between the conversion factors used in Part A of Model 2.

To find the relationship in the the conversion factors used in Part B of Model 2.

Explanation:

We have given that 1 meter = 39.4 inches.

Thus, from the calculations shown in part A of model 2, we can conclude that the quantity from meters to inches is converted as:

$1.5\times39.4=59$

Thus, 1.5 m =59 inches.

Also, the quantity from inches to meters is converted as:

$\frac{59}{39.4}=1.5$

Hence, 59 in = 1.5 m.

Next,

We have 1 L = 1.06 qt.

Thus, from the calculations shown in part B of model 2, we can conclude that the quantity from quarts to liters is converted as:

$\frac{186}{1.06}=175$

Thus, 186 quarts = 175 L.

Also, the quantity from liters to quarts is converted as:

$175\times1.06=186$

Hence, 175 L = 186 qt.

Final Answer:

We conclude that:

While converting from meters to inches, we multiply the quantity 1.5 by the equality quantity given.

While converting from incehs to meters, we divide the quantity 59 by the equality quantity given.

Also, While converting from quarts to liters, we divide the quntity 186 by the equality quantity given.

While converting from liters to quarts, we multiply the quntity 175 by the equality quantity given.

6 0

1 year ago