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ahrayia [7]
2 years ago
10

The temperature of the sun is 27 million degrees Fahrenheit. Use scientific notation to express the temperature.

Mathematics
2 answers:
Fantom [35]2 years ago
4 0

Answer:c

Step-by-step explanation:

Ipatiy [6.2K]2 years ago
3 0

Answer:

A

Step-by-step explanation:

We know million has 6 zeros.

So, 1 million would be written as:

1,000,000

Similarly, 27 million would be written as:

27,000,000

We know writing a number in scientific notation would make this a decimal in 1 decimal place, so we would select "2.7" as the base of the scientific number.

Now, how many places to the right do we need to go (in 2.7) to make it 27,000,000?

Counting, we see:  7 places

So, power of 10 would be "7", thus we can write:

2.7*10^7

Answer choice A is right

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cestrela7 [59]

Answer:

I've been trying to figure this out with out a chart and i keep confusing myself

Step-by-step explanation:

nothing

3 0
3 years ago
Where is 11/3 on a number line between 2 and 4
lions [1.4K]
Hiii! To work it out, you would have to do 11 ÷ 3. Which would equal 3.6 (Recurring).  If it's to one decimal place, it would be 4 if not, it would just be 3.6 ^^

Hope it helps!! Good luck~
7 0
3 years ago
Use a graphing calculator to graph f(x) = x+cos(kx). Use calculus to determine which values of k lead to a function with no loca
nataly862011 [7]

Answer:

Below, you can see the graph of the function:

f(x) = x + cos(k*x)

for different values of k, as follows:

red: k = 1

green: k = 2

orange: k = 0.

Now let's find the values of k such that our function does not have local maxima nor local minima.

First, remember that for a given function f(x), the local maxima or minima points are related to the zeros of the first derivate of f(x).

This means that if:

f'(x0) = 0.

Then x0 is a maxima, minima or an inflection point.

Then if a function is such that the f'(x) ≠ 0 , ∀x, then this function will not have local maxima nor minima.

Now we have:

f(x) = x + cos(k*x)

then:

f'(x) = 1  - k*sin(k*x)

This function will be zero when:

1 = k*sin(k*x)

1/k = sin(k*x)

now, remember that -1 ≤ sin(θ) ≤ 1

then if 1/k is smaller than -1, or larger than 1, we will not have zeros.

And this will happen if -1 < k < 1.

7 0
2 years ago
Determine if the triangle with the given sides is acute, obtuse, or right. 36, 49, 60
kotykmax [81]
<span>When given 3 triangle sides, to determine if the triangle is acute, right or obtuse:
</span>1) Square all 3 sides.
2) Sum the squares of the 2 shortest sides.
3) Compare this sum to the square of the 3rd side.

if sum > 3rd side²   Acute Triangle
if sum = 3rd side²   Right Triangle<span>
if sum < 3rd side²   Obtuse Triangle

1) 1,296   2,401   3,600
2) Sum = 3,697
3) </span><span>3,697 is greater than 3,600
Therefore, the triangle is acute.

Source:
http://www.1728.org/triantest.htm


</span>
4 0
2 years ago
According to data from a medical​ association, the rate of change in the number of hospital outpatient​ visits, in​ millions, in
GaryK [48]

Answer:

a) f(t)=0.001155[\frac{2}{3}t(t-1980)^{3/2}-\frac{4}{15}(t-1980)^{5/2}]+264,034,000

b) f(t=2015) = 264,034,317.7

Step-by-step explanation:

The rate of change in the number of hospital outpatient​ visits, in​ millions, is given by:

f'(t)=0.001155t(t-1980)^{0.5}

a) To find the function f(t) you integrate f(t):

\int \frac{df(t)}{dt}dt=f(t)=\int [0.001155t(t-1980)^{0.5}]dt

To solve the integral you use:

\int udv=uv-\int vdu\\\\u=t\\\\du=dt\\\\dv=(t-1980)^{1/2}dt\\\\v=\frac{2}{3}(t-1980)^{3/2}

Next, you replace in the integral:

\int t(t-1980)^{1/2}=t(\frac{2}{3}(t-1980)^{3/2})- \frac{2}{3}\int(t-1980)^{3/2}dt\\\\= \frac{2}{3}t(t-1980)^{3/2}-\frac{4}{15}(t-1980)^{5/2}+C

Then, the function f(t) is:

f(t)=0.001155[\frac{2}{3}t(t-1980)^{3/2}-\frac{4}{15}(t-1980)^{5/2}]+C'

The value of C' is deduced by the information of the exercise. For t=0 there were 264,034,000 outpatient​ visits.

Hence C' = 264,034,000

The function is:

f(t)=0.001155[\frac{2}{3}t(t-1980)^{3/2}-\frac{4}{15}(t-1980)^{5/2}]+264,034,000

b) For t = 2015 you have:

f(t=2015)=0.001155[\frac{2}{3}(2015)(2015-1980)^{1/2}-\frac{4}{15}(2015-1980)^{5/2}]+264,034,000\\\\f(t=2015)=264,034,317.7

3 0
3 years ago
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