This answer uses NMF, which you can find out about on my profile:
Preliminary work:
Following the BIDMAS order of operations, we can calculate part of it already, and that's the 2•4, which equals 8.
Therefore, the equation now reads:
8+x = y
x = 5:
8+5 = 13
13 ≠ 16
13 ≠ y
x = 4:
8+4 = 12
12 = 12
12 = y
Therefore, the pair is (4, 12)
So 5^2 -4^2 is 25-16 which is 9
6^2/9 is 36/9 which is 4 +9 is 13
13(13) is 169
The coefficient is 2 (it is always the number before the variable)
Step-by-step explanation:
x+x-7=11
2x+7=11
2x=18
2x/2=18/2 = x=9
9-7=2
So, FG=2
Answer: Yes it is possible to design more than one flag with these lengths because the two smaller side lengths 27 and 40 is greater than 50 which is the larger side length.
Step-by-step explanation:
